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bixtya [17]
3 years ago
12

Ewen has 48 whistle tiles and 16 blue tiles the cost of each white tile was £2 and the cost of each blue tile was £4 Work out th

e ratio of the total cost of the white tiles to the total cost of the blue tiles
Mathematics
1 answer:
AnnZ [28]3 years ago
6 0

Answer:

3:2

Step-by-step explanation:

Ewen has 48 white tiles and 16 blue tiles

The cost of each white tile was £2

The cost of each blue tile was £4

Therefore the total cost of 48 white tiles is

= 48×2

= £96

The total cost of 16 blue tiles is

= 16×4

= £64

The ratio of the total cost of the white tiles and blue tile can be calculated by dividing the cost of both tiles by their greatest common factor

The greatest common factor of £96 and £64 is 32

96/32 = 3

64/32= 2

Ratio= 3:2

Hence the ratio of the total cost of the white tiles to the blue tiles is 3:2

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6) −3 + 3k = −27<br> solve
erma4kov [3.2K]

Answer:

k = -8

Step-by-step explanation:

−3 + 3k = −27

⇔ -3 + 3k +3 = -27 +3

⇔ 3k = -24

⇔ k = -8

7 0
3 years ago
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Sergio039 [100]
The answer to this question is D and B
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3 years ago
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emmainna [20.7K]
              <span> Direct-substituting x = -2 gives 0/0, so we know that by the factor theorem, both the numerator and denominator have a factor of x + 2. From there, we can cancel out the conflicting factors and apply the limit.

We can factor the numerator and denominator to get:

x^3 - x^2 - x + 10 = (x + 2)(x^2 - 3x + 5)
x^2 + 3x + 2 = (x + 2)(x + 1).

So we have:

lim (x-->-2) (x^3 - x^2 - x + 10)/(x^2 + 3x + 2)
= lim (x-->-2) [(x + 2)(x^2 - 3x + 5)]/[(x + 2)(x + 1)]
= lim (x-->-2) (x^2 - 3x + 5)/(x + 1), by canceling out x + 2
= [2^2 - 3(-2) + 5]/(-2 + 1)
= (4 + 6 + 5)/(-1)
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7 0
3 years ago
The perimeter of an equilateral triangle is 15 inches more than the perimeter of a​ square, and the side of the triangle is 8 in
Setler [38]

<u>ANSWER:  </u>

The length of a side of the triangle is 17 inches.

<u>SOLUTION: </u>

Given, the perimeter of an equilateral triangle is 15 inches more than the perimeter of square.

And the side of the triangle is 8 inches longer than the side of the square.

Let the length of the side of a triangle be x.

And the length of the side of a square be y.

perimeter of triangle = a + b + c , where a , b, c represents side

perimeter of square = a + a + a +a , where a represents side

Given, the perimeter of an equilateral triangle is 15 inches more than the perimeter of square.  Hence we form a equation as

Then, x + x + x = 15 + y + y + y + y

3x = 15 + 4y ---- (1)

Now, given that, x = 8 + y ---- (2)

Substitute (2) in (1)

3(8 + y) = 15 + 4y

24 + 3y = 15 + 4y

4y – 3y = 24 – 15

y = 9

Now, substitute y value in (2)

x = 8 + 9  = 17

Hence, the length of a side of the triangle is 17 inches.

5 0
3 years ago
Please solve this for me.
Dominik [7]

standard form

a= 9×10^7

b= 5×10^8

7 0
3 years ago
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