Question

5. Factor the expression: y2 + 6y – 16 a. (y – 8)(y + 2) b. (y + 8)(y – 2) c. (y + 4)(y + 4) d. (y + 4)(y – 4)

Answer 1

For this case we have the following polynomial:

 $y^2 + 6y - 16$

We must find two numbers that comply with:

1) The algebraic sum of the numbers is equal to 6.

2) The multiplication of the numbers is equal to -16.

Therefore, factoring the polynomial we have:

 $(y + 8) (y-2)$

Answer:

The factored expression is:

b. (y + 8) (y - 2)

Answer 2

y2+6y-16

(y+8)(y-2)

your answer is B

Hope this helps :)