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vazorg [7]
3 years ago
11

I need help on this one too Will give 100 points!

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
3 0

\\ \sf\longmapsto 11x+13x+10

So

\\ \sf\longmapsto -150

  • Parents gave you 300$

Add them on all sides

\\ \sf\longmapsto 150

Done

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Explain why the expression below always has the same value, no matter what number other than zero you choose for p.
Natasha2012 [34]

Answer and explanation:

The expression P-2P+3P-4P cannot have the same values for different values of P. Let us illustrate this by substituting different values of P in the expression:

If P= 2

Substitute P=2 in the expression

2-2×2+3×2-4×2

=2-4+6-8

=-4

If P= 3

Substitute P=3 in the expression

3-2×3+3×3-4×3

=3-6+9-12

=-6

If P = 1

Substitute P=1 in the expression

1-2×1+3×1-4×1

= 1-2+3-4

= -2

If P = -2

Substitute P=1 in the expression

-2-2×-2+3×-2-4×-2

= -2+4-6+8

=4

Therefore we can see from the above that the expression has different values for different values of P

8 0
3 years ago
A bag of 60 skittles has an equal amount of red, orange, yellow, green, and purple what is the probability of choosing a green
ahrayia [7]

Answer:

1/5

Step-by-step explanation:

60 /5 = 12

So there are 12 red, 12 orange, 12 yellow, 12 green, 12 purple

P(green) = green/ total = 12/60 = 1/5

6 0
3 years ago
Read 2 more answers
I need help<br> someone pls
Alborosie

Answer:

≈ 66.5 m

Step-by-step explanation:

Using the sine ratio in the right triangle

sin12° = \frac{opposite}{hypotenuse} = \frac{d}{320} ( multiply both sides by 320 )

320 × sin12° = d , then

d ≈ 66.5 m ( to 1 dec. place )

8 0
3 years ago
HELP PRECALC NEED IN PROOF FORM
Vinil7 [7]

Hello, please consider the following.

We know the following, right ?

(\forall a, b \in \mathbb{R}) \left( sin(a+b)=sin(a)sin(b)+cos(a)cos(b) \right)

So, here, it gives.

Asin(\omega t+\phi)=Asin(\phi){\sf \bf sin(\omega t)}+Acos(\phi){\sf \bf cos(\omega t)}\\\\=c_2{\sf \bf sin(\omega t)}+c_1{\sf \bf cos(\omega t)}\\\\\text{ *** where }c_2=Asin(\phi) \text{ and } c_1=Acos(\phi) \text{ ***}

Do not hesitate if you need further explanation.

5 0
4 years ago
Which conditional statement has the same truth value as its converse
hodyreva [135]
In other words, you are looking for which one is the biconditional statement. 

A: This is true. Both the Conditional and Converse Statements are true. The Biconditional Statement would be this: The angles are bisected if and only if the angles have two congruent parts. This is true.

B: This is false. It is true as a conditional statement, but if you flip the p and q, it says that ALL acute angles are 60 degrees. This isn't true because a 35 degree angle or a 89 degree angle is also acute.

C: This is False. The conditional statement isn't true. The Converse statement is true but because the conditional statement is not then it is false. You can have two angles the aren't touching and they would be supplementary.

D:  This is False. The Conditional Statement is True but the converse is not. Not all congruent angles are vertical angles. You can have two angles that equal 90 degrees that form a line (supplementary) but they aren't vertical angles.

Therefore, your answer is A.


8 0
3 years ago
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