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babunello [35]
3 years ago
6

52, 25, 77, 77, ? , 451, 605

Mathematics
1 answer:
Andreas93 [3]3 years ago
5 0

Answer:

The missing number is 154.

Step-by-step explanation:

Adding the 52 and 25 gives 77.

Then reverse the 77 to get the next term (77).

Now we add the 2 77's to give 154.

So the next 2 terms after the second 77 are 154 and the reverse 451.

The missing number is 154.

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Which expressions are equivalent to the given sort 40 (there is more than one and the one selected is correct)
Basile [38]

Answer:

40 {}^{ \frac{1}{2} }

Step-by-step explanation:

The last one is also the answer

Using the rational exponet rule,

\sqrt[n]{ {x}^{m} }  = x {}^{ \frac{m}{n} }

Using this number,

\sqrt{40}

40 is the base so it will stay same. Remember this is a square root sign so our nth root is 2 so our denominator if the rational exponet is 2.

40 {}^{1}  = 40

so our numerator is 1 so

40 {}^{ \frac{1}{2} }

3 0
3 years ago
Which is the graph of y – 3 = (x + 6)?
velikii [3]

The Answer is A (The first graph in the photo), I attached the graph to help you see the answer for y-3=-\frac{2}{3}(x+6).

I hope you have a good day and please give me brainest if that is correct!

3 0
2 years ago
How to evaluate the limit
anzhelika [568]
\displaystyle\lim_{x\to2}\frac{x^2-x+6}{x+2}

Both the numerator and denominator are continuous at x=2, which means the quotient rule for limits applies:

\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2

Perhaps you meant to write that x\to-2 instead? In that case, you would have

\displaystyle\lim_{x\to-2}\frac{x^2-x+6}{x+2}=\lim_{x\to-2}\frac{(x+2)(x-3)}{x+2}=\lim_{x\to-2}(x-3)=-2-3=-5
4 0
3 years ago
If 36 is 25% of the total, what is the total?
Alexandra [31]
Answer:144
Explanation: 25% of the total in other words means that it is 1/4 (a quarter). You could just multiply 36 by 4 to get the total (100%). If u want to verify, just multiply 144 by 0.25 and u should get 36.
7 0
3 years ago
If the range of the function y = f(x) is {y | y ≥ 11, y ∈ R}, then the range of the new function g(x) = f(x + 2) - 3 is
mafiozo [28]

Answer:

y ≥ 8

Explanation:

Note that if f(x) is transformed into f(x + a) - b

The original functions is shifted a units to the left and b units downward.

Horizontal shifting will not affect the range of the function, only vertical shifting will change its range.

From the given, g(x) is the transformation of f(x) with

g(x)=f(x+2)-3_{}

f(x) is shifted 2 units to the left and 3 units downward, we will disregard the horizontal shifting.

Since f(x) has a range of y ≥ 11, and g(x) is 3 units downward, the range will also move 3 units downward.

y ≥ 11 - 3

The answer is y ≥ 8

3 0
10 months ago
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