Answer:
Base area (B) should not be added.
Step-by-step explanation:
Base area should not be added as cone is not solid. Only Lateral surface area is sufficient in order to find the required paper.
The answer to the problem is 6,-6
Answer:
The graph is uploaded in the attachment.
The value of x is 2.625.
Step-by-step explanation:
- let us plot f(x), g(x) on y-axis
so, f(x)=y and g(x)=y.
- the first equation can be written as y=5-2x
- the general equation of a straight is y=mx+c
( where m is the slope and c is the y-intercept )
- now comparing given equation with the general equation mentioned above, the slope of first line is -2 and its y-intercept is 5
- the slope of second equation i.e, y=(2/3)x-2 is 2/3 and its y-intercept is -2.
- now plot the graph using above information.
(y-intercept is the the coordinate of a point where the line intersects y-axis)
(slope is the angle made by the line with the x-axis)
- by seeing the graph, the value of x is 2.625.
Given = b = 20cm, A = 500cm2 l=?
A = l×b,
500= l×20
l= 25
<em>THE LENGTH IS 25 CM</em>
Answer:
(1 ) Inner curved surface area of the well is 109.9 sq. meters.
(2) The cost of plastering the total curved surface area is 4396.
Step-by-step explanation:
The inner diameter = 3.5 m
Depth of the well = 10 m
Now, Diameter = 2 x Radius
⇒R = D/ 2 = 3.5/2 = 1.75
or, the inner radius of the well = 1.75 m
CURVED SURFACE AREA of cylinder = 2πr h
⇒The inner curved surface area = 2πr h = 2 ( 3.14) (1.75)(10)
= 109 sq. meters
Hence, the inner curved surface area of the well is 109.9 sq. meters.
Now, the cost of plastering the curved area is 40 per sq meters
So, the cost of total plastering total area = 109.9 x(Cost per meter sq.)
= 109.9 x (40)
= 4396
Hence, the cost of plastering the total curved surface area is 4396.
