Question

Given: FKLM is a trapezoid, KL = 26 FM = 49, FK = 10, m∠F = 48º Find: Area of FKLM

Answer 1

Answer:

Area of the trapezoid is 278.63 square units.

Step-by-step explanation:

In this question figure of the trapezoid is not given;

If the figure is same as figure attached,

FKLM is the trapezoid having

Side FK = 10 units

KL = 26 units

m∠F = 48°

Now in ΔKFP,

sin48° = $\frac{PK}{FK}$

0.7431 = $\frac{PK}{10}$

PK = 7.43 units

Now area of the trapezoid FKLM = $\frac{1}{2}(\text{sum of parallel sides)}(\text{distance between parallel sides})$

= $\frac{1}{2}(26+49)(7.43)$

= 278.63 square units

Therefore, area of the trapezoid will be 278.63 square units.