Given: FKLM is a trapezoid, KL = 26 FM = 49, FK = 10, m∠F = 48º Find: Area of FKLM
1 answer:
Answer:
Area of the trapezoid is 278.63 square units.
Step-by-step explanation:
In this question figure of the trapezoid is not given;
If the figure is same as figure attached,
FKLM is the trapezoid having
Side FK = 10 units
KL = 26 units
m∠F = 48°
Now in ΔKFP,
sin48° =
0.7431 =
PK = 7.43 units
Now area of the trapezoid FKLM =
=
= 278.63 square units
Therefore, area of the trapezoid will be 278.63 square units.
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Step-by-step explanation:
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So in this case, we have to replace the known value.
y=3
y=-2x+3
3=-2x+3
Then we leave our unknown value alone.
= x
In this case, our x value would be 0.
We check it...
3=-2(0)+3
3=0+3
3=3
So y=3 x=0
For the second one we have...
y=3x+2
y=-3x-4
For this we substitute the y in any of the equation...
3x+2=-3x-4
We move the unknown values to one side and the ones without unlown values to the other side...
3x+3x=-4-2
Then we solve
6x=-6
Then we leave the unknown value alone.
x=
Then solve for x.
x= -1
Then for our y value we return to one of the original equations and substitute the x value.
y=3x+2
y=3(-1)+2
y=-3+2
y=-1
y=-3x-4
y=-3(-1)-4
y=3-4
y=-1
So in this case we got that x= -1 and y= -1
y=3
y=-2x+3
3=-2x+3
Then we leave our unknown value alone.
In this case, our x value would be 0.
We check it...
3=-2(0)+3
3=0+3
3=3
So y=3 x=0
For the second one we have...
y=3x+2
y=-3x-4
For this we substitute the y in any of the equation...
3x+2=-3x-4
We move the unknown values to one side and the ones without unlown values to the other side...
3x+3x=-4-2
Then we solve
6x=-6
Then we leave the unknown value alone.
x=
Then solve for x.
x= -1
Then for our y value we return to one of the original equations and substitute the x value.
y=3x+2
y=3(-1)+2
y=-3+2
y=-1
y=-3x-4
y=-3(-1)-4
y=3-4
y=-1
So in this case we got that x= -1 and y= -1