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3 years ago

ANSWER THESE MATHS PROBLEMS PLEASE IK THEY'RE EASY BUT I CANT RIGHT NOW

Mathematics

1 answer:

Mariana [72]3 years ago

6 0

1 is 55
2 is 70
3 is 110
4 is 6
5 is 30
6 is 500
7 is 5
8 is 40 ft
9 is 20
10 is 1 hour

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Find the value of the variable.

Zielflug [23.3K]

Answer:

x = 8, y = $8\sqrt{2}$

Step-by-step explanation:

$a^2+b^2=c^2$

$8^2+8^2=c^2$ Both 8 and x sides are congruent so they're equal.

$64+64=c^2$ Add 64 + 64.

$c^2=128$ Square root 128

$c^2=8\sqrt{2}$

Final answers: x = 8, y = $8\sqrt{2}$

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3 years ago

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1+1 ......................................................................................

aleksley [76]

Answer:

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3 years ago

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The table shows how many books the students in Bergdalsskolan list during the summer. There were 48 students who list 4 books. a

Juliette [100K]

Step 1:

First, find the total number of students.

Let the total number of students = m

Step 2:

Find the total number of students using the percentage of 4 books.

48 students listed 4 books with a percentage of 16%

$\begin{gathered} 48\text{ = 16\% of m} \\ 48\text{ = }\frac{16}{100}\text{ }\times\text{ m} \\ 48\text{ = }\frac{16m}{100} \\ \text{Cross multiply} \\ 16m\text{ = 48 }\times\text{ 100} \\ 16m\text{ = 4800} \\ \text{m = }\frac{4800}{16} \\ \text{m = 300} \end{gathered}$

Hence, there are 300 students.

$\begin{gathered} \text{Number of students that had 1 book = 24\% of 300} \\ =\text{ }\frac{24}{100}\text{ }\times\text{ 300} \\ =\text{ }\frac{7200}{100} \\ =\text{ 72 students} \end{gathered}$

72 students had 1 book.

b) What percentage more read 2 books than 4 books?

percentage that read 2 books = 36%

percentage that read 4 books = 16%

36 - 16 = 20%

There are 20% students that read 2 books than 4 books.

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2 years ago

The Honor Society held a canned goods drive. They ran great advertising campaigns and collections increased. The following table

andrezito [222]

The cans are increasing at a linear rate.

If you look at the number of cans collected, you will see that they are increasing by 5 each time. Since the rate of change is the same each day, it is a linear pattern.

7 0

3 years ago

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Look at the picture. Solve for y

Mumz [18]

Answer:

y = 5

Step-by-step explanation:

Equation:

m<DGF = m<DGE + m<EGF

Given:

m<DGF = 12y - 5

m<DGE = 5y + 6

m<EGF = 24

Work:

m<DGF = m<DGE + m<EGF

12y - 5 = 5y + 6 + 24

12y - 5 = 5y + 30

12y - 5y = 30 + 5

7y = 35

y = 5

5 0

3 years ago