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Dafna11 [192]
3 years ago
11

Solve the following system of equations graphically. Click on the graph until the correct solution of the system appears.

Mathematics
2 answers:
harkovskaia [24]3 years ago
8 0

Answer:

the first pic

kodGreya [7K]3 years ago
3 0

Answer:

The first picture

Step-by-step explanation:

Its the only one that has the line x=1

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The functions f(x) and g(x) are defined below.
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3 years ago
A right triangle has an area of 18 The length of each leg is 6 inches. If the triangle is not an isosceles triangle, what are al
ladessa [460]

Given:

Area of a right triangle = 18 sq. inches

Length of one leg = 6 inches

To find:

The length of another leg.

Solution:

We know that, the area of a triangle is

A=\dfrac{1}{2}\times base\times height

In a right angle triangle, the area of the triangle is

A=\dfrac{1}{2}\times leg_1\times leg_2

Putting A=18 and leg_1=6, we get

18=\dfrac{1}{2}\times 6\times leg_2

18=3\times leg_2

Divide both sides by 3.

\dfrac{18}{3}=leg_2

6=leg_2

Both legs are equal so the given triangle is an isosceles right triangle.

If the triangle is not isosceles triangle, then the length of legs are factors of 36 because half of 36 is 18.

Therefore, the possible pairs of legs are 1 and 36, 2 and 18, 3 and 12, 4 and 9, 6 and 6, 9 and 4, 12 and 3, 18 and 2, 36 and 1.

5 0
2 years ago
A fair coin is flipped twelve times. What is the probability of the coin landing tails up exactly nine times?
seraphim [82]

Answer:

P\left(E\right)=\frac{55}{1024}

Step-by-step explanation:

Given that a fair coin is flipped twelve times.

It means the number of possible sequences of heads and tails would be:

2¹² = 4096

We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula

nCr=\frac{n!}{r!\left(n-r\right)!}

Plug in n = 12 and r = 9

       =\frac{12!}{9!\left(12-9\right)!}

       =\frac{12!}{9!\cdot \:3!}

       =\frac{12\cdot \:11\cdot \:10}{3!}            ∵ \frac{12!}{9!}=12\cdot \:11\cdot \:10

       =\frac{1320}{6}                   ∵ 3!\:=\:3\times 2\times 1=6

       =220

Thus, the probability will be:

P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}

         =\frac{220}{4096}

         =\frac{55}{1024}

Thus, the probability of the coin landing tails up exactly nine times will be:

P\left(E\right)=\frac{55}{1024}

4 0
3 years ago
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