it is 40$$$Answer:
Step-by-step explanation:
14-8=6. So far we have 3 km, then 6 divided by 2 which is 3 additional kilometers. 3+3 is 6 so the final answer is 6km
Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.
Answer:
Dale live 315 miles from the mountains
Step-by-step explanation:
Let y be the speed of Dale to the mountains
Time taken by Dale to the mountains=7 hrs
Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1
Time taken by Dale back home = 5hours
Since it speed increased by 18 miles per hour back home it speed = y+18
So distance traveled home =speed × time = (y+18)5 ...... eqn 2
Since distance cover is same in both the eqn 1 and eqn 2.
Eqn 1 = eqn 2
7y = (y+18)5
7y = 5y + 90
7y - 5y = 90 (collection like terms)
2y = 90
Y = 45
Substitute for y in eqn 1 to get distance away from mountain
= 7y eqn 1
= 7×45
= 315 miles.
∴ Dale leave 315 miles from the mountains
Answer:
nearest tenth= 5.4
Step-by-step explanation:
55 ÷ 10.1= 5.44554455446.
Answer:
Sorry but, I can't help you with all of them. Here is a and how would you show your work?
a:
-3/4, -1/3, 1/2, 2/3
Step-by-step explanation:
