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PIT_PIT [208]
2 years ago
7

F(x) = 6x+2, find f (x+3)

Mathematics
2 answers:
nikklg [1K]2 years ago
3 0

Answer:

6x+20

Step-by-step explanation:

F(x) = 6x+2

f(x+3) means replace x with x+3

F(x+3) = 6(x+3)+2

         = 6x+18+2

         = 6x+20

Alika [10]2 years ago
3 0

Answer:

A; F(x+3) = 6x^2 + 20x + 6

Step-by-step explanation:

To find it you just would multiply F(x) onto the other side. So it would look like this:

           F(x+3) = 6x + 2 (x+3)            

          F(x+3) = 6x^2 + 2x + 18x + 6            *combine like terms getting you

           F(x+3) = 6x^2 + 20x + 6    

Hope this helped!!

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Which number line shows the solution 1/2x-2>0
Ymorist [56]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

\frac{1}{2}x-2>0

Solve for x

\frac{1}{2}x>2

x>4

The solution is the interval ------> (4,∞)

All real numbers greater than 4

In a number line, the solution is the shaded area at right of x=4 (open circle, the number 4 is not included in the solution)

see the attached figure

7 0
3 years ago
Please help i will mark brainliest for anyone who can help me 15 points on the line
gregori [183]

Answer:

A: a^3

B: c^1 or just c

Step-by-step explanation:

Subtract the exponents

6 0
3 years ago
A married couple had a combined annual income of 63,000. The wife made 7,000 more than her husband. What was each of their incom
Alchen [17]
The wife made 33,500 and the husband made 29,500
4 0
3 years ago
Read 2 more answers
Which sheep has a larger area of rectangle that is 7" by 3 fourths inch or a square with side length of 2 1/2 inches
Gnesinka [82]
If you multiply 7 by .75 you get 5.25
rectangle = area = 5.25
then multiply 2.5 by itself and you get 6.25
square area = 6.25
So the 2 1/2 inch square has more room
7 0
3 years ago
HELP ME!!!
larisa [96]

Answer:

  -2, 8/3

Step-by-step explanation:

You can consider the area to be that of a trapezoid with parallel bases f(a) and f(4), and width (4-a). The area of that trapezoid is ...

  A = (1/2)(f(a) +f(4))(4 -a)

  = (1/2)((3a -1) +(3·4 -1))(4 -a)

  = (1/2)(3a +10)(4 -a)

We want this area to be 12, so we can substitute that value for A and solve for "a".

  12 = (1/2)(3a +10)(4 -a)

 24 = (3a +10)(4 -a) = -3a² +2a +40

  3a² -2a -16 = 0 . . . . . . subtract the right side

  (3a -8)(a +2) = 0 . . . . . factor

Values of "a" that make these factors zero are ...

  a = 8/3, a = -2

The values of "a" that make the area under the curve equal to 12 are -2 and 8/3.

_____

<em>Alternate solution</em>

The attachment shows a solution using the numerical integration function of a graphing calculator. The area under the curve of function f(x) on the interval [a, 4] is the integral of f(x) on that interval. Perhaps confusingly, we have called that area f(a). As we have seen above, the area is a quadratic function of "a". I find it convenient to use a calculator's functions to solve problems like this where possible.

5 0
3 years ago
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