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3 years ago

What is the equation of a circle whose center is (2,0) and has a radius= 9?

2 answers:

6 0

The equation of a circle is: (x - h)² + (y - k)² = radius² where (h, k) is the center. Now just plug in your given information and simplify.

(x - 2)² + (y - 0)² = 9²

Your equation is:
(x - 2)² + y² = 81

HACTEHA [7]3 years ago

6 0

(x-2)²+(y-0)²=9²
you need simplify it.
center(a,b) radius=R
(x-a)²+(y-b)²=R²

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In how many ways can 7 people line if A needs to be first or last and B needs to be in the middle

12345 [234]

Answer:

Assuming person A and person B are part of the 7 people, there are 10 ways the 7 people can line up if A needs to be first or last and B needs to be in the middle.

Step-by-step explanation:

There are 2 places for A (first, last) and 5 places for B (anywhere but first or last). 2 x 5 = 10.

8 0

2 years ago

Please help these are not easy for me

Pavel [41]

Answer:

12a^2 - 9a + 5

Step-by-step explanation:

(5a^2 - 6a - 4) - (-7a^2 + 3a - 9)

5a^2 + 7a^2 = 12a^2

-6a - 3a = -9a

-4 + 9 = 5

12a^2 - 9a + 5

7 0

2 years ago

Is the set of numbers one 1,5,25 and 125 a geometric sequence

Strike441 [17]

Short answer: Yes.
Each member of the sequence is multiplied by 5 to get to the next member of the sequence.

Find the general equation.
tn = a*5^(n - 1)

Example
t4 = 1*5^(4 - 1)
t4 = 1*5^3
t4 = 125 just as the sequence shows.

t5 = 1^5^4
t5 = 625 Any member of the sequence can be found this way.

6 0

2 years ago

Pls help . (when u get in the document its duplicated)

riadik2000 [5.3K]

The picture is not showing up

6 0

2 years ago

Read 2 more answers

Question in picture A) 16/63 B)-16/63 C) 63/16 D) -63/16

Orlov [11]

ANSWER
$\tan(x + y) = - \frac{63}{16}$

EXPLANATION

We were given that,

$\csc(x) = \frac{5}{3}$

This implies that,

$\sin(x) = \frac{3}{5}$

We use the Pythagorean identity

$\sin^{2} (x) + \cos^{2} (x)= 1$
to get,

$\cos(x) = \sqrt{1 - ( { \frac{3}{5} })^{2}} = \frac{4}{5}$

We were also given that,

$\cos(y) = \frac{5}{13}$

This means that,

$\sin(y) = \sqrt{1 - {( \frac{5}{13}) }^{2} } = \frac{12}{13}$

This is because,

$0 < \: x \: < \frac{\pi}{2}$

$0 < \: y \: < \frac{\pi}{2}$

This angles are in the first quadrant so we pick the positive values.

$\tan(x + y) = \frac{ \sin(x + y) }{ \cos(x + y) }$

$\tan(x + y) = \frac{ \sin(x ) \cos(y) + \sin(y) \cos(x) }{ \cos(x) \cos(y) - \sin(x) \sin(y) }$

$\tan(x + y) = \frac{ \frac{3}{5} \times \frac{5}{13} + \frac{12}{13} \times \frac{4}{5} }{ \frac{4}{5} \times \frac{5}{13} - \frac{3}{5} \times \frac{12}{13} }$

$\tan(x + y) = - \frac{63}{16}$

The correct answer is D

4 0

3 years ago