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NemiM [27]
3 years ago
14

What are the missing parts that correctly complete the proof?

Mathematics
1 answer:
Pepsi [2]3 years ago
3 0

Answer:

1. point p is on the perpendicular bisector of AB¯¯¯¯¯- given

2. AXP≅BXP. definition of bisector

3. ∠PXA and ∠PXB are right angles. definition of perpendicular

4. ∠PXA≅ ∠PXB. All right angles are congruent.

5.PX¯¯¯¯¯≅PX¯¯¯¯¯ ​ Reflexive Property of Congruence

6.AXP≅AXQ. SAS Congruence Postulate

7.AX¯¯¯¯¯≅BX¯¯¯¯¯

8.Point P is equidistant from the endpoints of AB¯¯¯¯¯. Definition of equidistant

Step-by-step explanation:

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A teacher offers 8 extra credit assignments. what is the domain of this graph?
UkoKoshka [18]

Answer:

C

Step-by-step explanation:

This is the shows the constant value on the X-axis

3 0
3 years ago
Im 10 years old and my sister is 4 years younger than me. 60 years later how old is my sister?
Morgarella [4.7K]
Your sister would be 66.
When you are 10, your sister would be 6 (10-4=6)
60 years later, you would be 70, and your sister would still be 4 years younger.
8 0
3 years ago
Timothy has a fenced-in garden in the shape of a
sattari [20]

Answer:

From the attached graphic we see that

rhombus side =   Sqr Root [(Long Diagonal / 2) ^ 2 + (Short Diagonal / 2) ^ 2]

rhombus side =   Sqr Root [(24/2)^2 + (18/2)^2]

rhombus side =   Sqr Root [144 + 81]

rhombus side =  Sqr Root (225)

rhombus side = 15 feet

Step-by-step explanation:

7 0
3 years ago
What is the solution to 5x < 30
max2010maxim [7]

Let's solve your inequality step-by-step.

5x<30

Step 1: Divide both sides by 5.

5x

5

<

30

5

x<6

7 0
3 years ago
A box contains 17 balls numbered 1 through 17. Two balls are drawn in succession without replacement. If the second ball has the
Brilliant_brown [7]

Answer:

1 ; 7 /17

Step-by-step explanation:

17 balls numbered 1 through 17

Picking without replacement :

If the second ball picked = 4

P(first ball has a smaller number)

Numbers less Than = (3, 2, 1)

P(number less than second ball Given 4 is drawn for second ball) :

= (3/17 * 1/16) ÷ (3/17 * 1/16) +) 14/17 * 0)

= (3 / 272) / (3 /272) * 0

= 3 / 272 * 272 / 3

= 1

2.)

(8/17 * 7/8) ÷ (8/17 * 7/8) + (9/17 * 1/17)

7/17 ÷ (7 /17) + 10/17

7 /17 ÷ 17/17

7/17 ÷ 1

7 /17

7 0
3 years ago
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