for example if you have 3x^2+2x-1 then a=3 b=2 and c=-1 you plug those into the formula and solve to get the formula just look it up and go to images
The two equations given in the question are
y = - 3x
And
y = 6x - 9
Let us now substitute the value of y from the first equation to the second equation, we get
y = 6x - 9
- 3x = 6x - 9
-3x - 6x = - 9
- 9x = - 9
Multiplying both sides of the equation by -1 we get
9x = 9
x = 9/9
= 1
Now let us put the value of x in the first equation, we get
y = - 3x
= - (3 * 1)
= - 3
Answer:
Step-by-step explanation:
It’s suppose to say and a y intercept then the answer would be
Y= 2/3x -2
9x - 2y = 11 ... (i)
5x - 2y = 15 ... (ii)
Subtracting equation (ii) from (i) we get;
4x + 0 = -4
4x=-4 , x = -1
Replacing x = -1 in equation (i) we get;
9(-1) - 2y = 11
-9 - 2y = 11
-2y = 20
y = 20 ÷ -2 = -10
The solution to the system of equations is (-1,-10).
Answer:2
Step-by-step explanation:
15/3 = 5
15/2 = 7.5
+1
= 13
15 - 13 = 2