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Vitek1552 [10]
3 years ago
6

Find the quotient of the quantity 4 times x to the 3rd power times y plus 12 times x to the 2nd power times y to the 3rd power m

inus 20 times x times y all over 4 times x times y. x2 + 3xy2 + 5
x2 + 3xy − 5
4x3y + 12x2y3 − 5
x2 + 3xy2 − 5
Mathematics
2 answers:
noname [10]3 years ago
7 0

Answer:

The quotient is:

x^2+3xy^2-5

Step-by-step explanation:

We have to find the quotient of the algebraic quantity:

\dfrac{4x^3y+12x^2y^3-20xy}{4xy}

i..e we have dividend as:

4x^3y+12x^2y^3-20xy , divisor as: 4xy

Now we can write our dividend term as:

4x^3y+12x^2y^3-20xy=4xy(x^2+3xy^2-5)

Hence, the we can represent our expression as:

\dfrac{4x^3y+12xy^3-20xy}{4xy}=\dfrac{4xy(x^2+3xy^2-5)}{4xy}\\\\=x^2+3xy^2-5

Hence, the quotient is:

x^2+3xy^2-5

asambeis [7]3 years ago
6 0
We have to find the quotient :
( 4 x³ y + 12 x² y³ - 20 x y ) / ( 4 x y ) =
= 4 x y ( x² + 3 x y² - 5 ) / ( 4 x y ) =   ( Then 4 x y will be cancelled )
= x² + 3 x y² - 5
Answer:
 D ) x² + 3 x y² - 5
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Answer:

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The given equations relates to the property of equality of values;

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