Help me please! √-44

Mathematics

2 answers:

sukhopar [10]4 years ago

5 0

6.6 Is the rounded approximate answer

Pavlova-9 [17]4 years ago

4 0

2i√11

The I can also be behind the 11

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Question 6 (Essay Worth 2 points) Find all polar coordinates of point P = (2, 14°).

andrey2020 [161]

Answer:

(2,14°+360n) and (-2,14°+(2n+1)180°)

Step-by-step explanation:

You start out with (2, 14°)

The polar coordinate can be written as (r, 0) = (r, 0+2nπ) or

(r,0)=(-r,0+2(n=1)π), where n is any integer.

The polar coordinates point : p=(r,0) = (2,14°)

For the positive value of r, the polar coordinate can be written as

p=(2,14°) = (2,14°+360n°), where n is any integer.

For the negative value of r , the polar coordinate can be written as

p=(2,14°) = (-2,14°+(2n+1)180°), where n is any integer.

All the polar coordinates of point P are(2,14°+360n) and (-2,14°+(2n+1)180°).

4 0

3 years ago

The vertices of a triangle ABC are A(7, 5), B(4, 2), and C(9, 2). What is measure of angle ABC? 30° 45° 56.31° 78.69°

GenaCL600 [577]

The measure of angle ABC is 45°

Explanation

Vertices of the triangle are: A(7, 5), B(4, 2), and C(9, 2)

According to the diagram below....

Length of the side BC (a) $=\sqrt{(4-9)^2+(2-2)^2}= \sqrt{25}= 5$

Length of the side AC (b) $= \sqrt{(7-9)^2 +(5-2)^2}= \sqrt{4+9}=\sqrt{13}$

Length of the side AB (c) $= \sqrt{(7-4)^2 +(5-2)^2} =\sqrt{9+9}=\sqrt{18}$

We need to find ∠ABC or ∠B . So using Cosine rule, we will get...

$cosB= \frac{a^2+c^2-b^2}{2ac} \\ \\ cos B= \frac{(5)^2+(\sqrt{18})^2-(\sqrt{13})^2}{2*5*\sqrt{18} }\\ \\ cosB= \frac{25+18-13}{10\sqrt{18}} =\frac{30}{10\sqrt{18}}=\frac{3}{\sqrt{18}}\\ \\ cosB=\frac{3}{3\sqrt{2}} =\frac{1}{\sqrt{2}}\\ \\ B= cos^-^1(\frac{1}{\sqrt{2}})= 45 degree$