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kodGreya [7K]
3 years ago
7

Find the area of rectangle $BCEF$ . Round the area to the nearest whole number, if necessary.

Mathematics
1 answer:
WINSTONCH [101]3 years ago
5 0

Answer:

999

Step-by-step explanation:

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Which polynomial represents the sum below?
marin [14]

Answer:

C

Step-by-step explanation:

(4x^2+1)+(4x^2+x+2)= \\\\(4x^2+4x^2)+x+(1+2)= \\\\8x^2+x+3

Hope this helps!

7 0
3 years ago
Evey month the bank withdraws $15 from netsy checking account as a service fee . Betsy had budgeted $75 for the next few fees se
Nadusha1986 [10]
15x≤75
x<span>≤5
</span>service fee will be covered for 5 months

3 0
3 years ago
Enlarge the triangle by scale factor of -1/3
Bess [88]

The attached image represents the triangle after it has been enlarged

<h3>How to enlarge the triangle?</h3>

The given parameters are:

  • Scale factor, k = -1/3
  • Center, (a,b) = (-1,2)

From the graph, the coordinates of the triangle are:

A = (-4,2)

B = (-4,-4)

C = (-1,-4)

The rule of dilation is calculated using:

(x,y) \to (k(x - a) + a, k(y - b) + b)

So, we have:

A' = (-\frac 13(-4 +1) - 1, -\frac 13(2 - 2) + 2)

A' = (0, 2)

B' = (-\frac 13(-4 +1) - 1, -\frac 13(-4 - 2) + 2)

B' = (0, 4)

C' = (-\frac 13(-1 +1) - 1, -\frac 13(-4 - 2) + 2)

C' = (-1, 4)

See attachment for the image of the triangle, after it has been enlarged

Read more about dilation at:

brainly.com/question/3457976

#SPJ1

4 0
2 years ago
We wish to give a 90% confidence interval for the mean value of a normally distributed random variable. We obtain a simple rando
coldgirl [10]

Answer: (9.27025,\ 11.12975)

Step-by-step explanation:

Given : Sample size : n= 9

Degree of freedom = df =n-1 =8

Sample mean : \overline{x}=10.2

sample standard deviation : s= 1.5

Significance level ; \alpha= 1-0.90=0.10

Since population standard deviation is not given , so we use t- test.

Using t-distribution table , we have

Critical value = t_{\alpha/2, df}=t_{0.05 , 8}=1.8595

Confidence interval for the population mean :

\overline{x}\pm t_{\alpha/2, df}\dfrac{s}{\sqrt{n}}

90% confidence interval for the mean value will be :

10.2\pm (1.8595)\dfrac{1.5}{\sqrt{9}}

10.2\pm (1.8595)\dfrac{1.5}{3}

10.2\pm (1.8595)(0.5)

10.2\pm (0.92975)

(10.2-0.92975,\ 10.2+0.92975)

(9.27025,\ 11.12975)

Hence, the 90% confidence interval for the mean value= (9.27025,\ 11.12975)

6 0
3 years ago
3/5 of a condductors club went on a camping trip. 39 people went how mant stayed home
mafiozo [28]
39 / 3/5 = 

39 *5 = 195 / 3 = 65

65-39 = 26 people stayed home
7 0
4 years ago
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