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3 years ago

Need help on my work I'm marking you the brainiest if the answer is right! hurry pleaseeeeeeee need help quick asap!

Mathematics

1 answer:

lianna [129]3 years ago

7 0

I believe its the first one

--y<2/3--

Slope - up 2 over 3

dotted line because there is no or equal to

y< so shade down

--y>/=-x+2--

Negative slope

or equal to so solid line

y intercept 2

Y> shade up

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Which are dependent events?

mezya [45]

Answer:

D. taking two marbles from a box without replacing the first marble are dependent events

$----------$

hope it helps

have a great day!!

6 0

3 years ago

Read 2 more answers

Please help! I am so confused on this, I've probably been stuck on it for at least an hour.

julsineya [31]

9514 1404 393

Answer:

see attached for the drawing

slope = -1/2

Step-by-step explanation:

For the rise of -1 and the run of 2, the slope is ...

m = rise/run = -1/2 . . . . slope in simplest form

<em>Additional comments</em>

It usually works best if you can identify points on the graph where the line crosses grid intersections. Then the number of squares in each direction can be counted easily. If you work with two grid intersections that are closest together, then the ratio of rise to run will already be in reduced form.

On this graph, there are other grid crossing points that are 4, 6, 8 units to the right or left of the one where we started. You need to remember that "run" is positive in the "right" direction, and "rise" is positive in the "up" direction.

We have shown the "rise" and "run" lines above the graphed line. They can also be shown below the graphed line.

Here, the grid squares are 1 unit in each direction. You need to pay attention to the scale, because some graphs have different numbering vertically than horizontally. The values for "rise" and "run" need to be figured using the appropriate scale.

5 0

3 years ago

HELP PLEASE!!! I need help with 94 if you could show the steps that would be very helpful!

aksik [14]

A combination is an unordered arrangement of r distinct objects in a set of n objects. To find the number of permutations, we use the following equation:

n!/((n-r)!r!)

In this case, there could be 0, 1, 2, 3, 4, or all 5 cards discarded. There is only one possible combination each for 0 or 5 cards being discarded (either none of them or all of them). We will be the above equation to find the number of combination s for 1, 2, 3, and 4 discarded cards.

5!/((5-1)!1!) = 5!/(4!*1!) = (5*4*3*2*1)/(4*3*2*1*1) = 5

5!/((5-2)!2!) = 5!/(3!2!) = (5*4*3*2*1)/(3*2*1*2*1) = 10

5!/((5-3)!3!) = 5!/(2!3!) = (5*4*3*2*1)/(2*1*3*2*1) = 10

5!/((5-4)!4!) = 5!/(1!4!) = (5*4*3*2*1)/(1*4*3*2*1) = 5

Notice that discarding 1 or discarding 4 have the same number of combinations, as do discarding 2 or 3. This is being they are inverses of each other. That is, if we discard 2 cards there will be 3 left, or if we discard 3 there will be 2 left.

Now we add together the combinations

1 + 5 + 10 + 10 + 5 + 1 = 32 choices combinations to discard.

The answer is 32.

-------------------------------

Note: There is also an equation for permutations which is:

n!/(n-r)!

Notice it is very similar to combinations. The only difference is that a permutation is an ORDERED arrangement while a combination is UNORDERED.

We used combinations rather than permutations because the order of the cards does not matter in this case. For example, we could discard the ace of spades followed by the jack of diamonds, or we could discard the jack or diamonds followed by the ace of spades. These two instances are the same combination of cards but a different permutation. We do not care about the order.

I hope this helps! If you have any questions, let me know :)

7 0

3 years ago

2x/3 + 1 = 3

ASHA 777 [7]

X = 6 or in other word d

7 0

4 years ago

Read 2 more answers

The two dot plots show the number of miles ran by 14 students at the beginning and at the end of the school year compare each me

Naddika [18.5K]

The two dot plots are missing, so i have attached it.

Answer:

The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles

Step-by-step explanation:

From the attached image, we are told to compare the means for each plot to the nearest tenth.

Mean = Σx/n

Now, from the image, total number of miles run by the 14 students at the beginning of the school year is;

(1 × 7) + (2 × 8) + (4 × 9) + (4 × 10) + (2 × 11) + (1 × 12) = 133

Mean of miles run at the beginning of the school year = 133/14 = 9.5 miles

Again, from the table, total miles run at the end of the school year = (2 × 8) + (2 × 9) + (4 × 10) + (3 × 11) + (3 × 12) = 143

Mean of miles run at the end of the school year = 143/14 = 10.2 miles

Thus;

The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles

5 0

3 years ago