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gizmo_the_mogwai [7]

3 years ago

7

five times the difference of a number and three is the same as three increased by five times the number plus 3 times the number

1 answer:

sergij07 [2.7K]3 years ago

4 0

Yes Yes Yes Yes Yes 63

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A man weighing 800 N is hanging from a 2 mm diameter titanium wire with a cross-section of 3 x 10^-6 m^2. Will the wire break?

DENIUS [597]

Answer:

Since stress is greater than ultimate strength, the wire will break.

Step-by-step explanation:

The titanium wire is experimenting an axial load. Ultimate strength equals $2.20\times 10^{8}\,Pa$ . The wire shall break if and only if stress is at least equal to ultimate strength. The equation for axial stress ( $\sigma$ ), measured in pascals, in the wire with circular cross-section is:

$\sigma = \frac{4\cdot F}{\pi\cdot D^{2}}$ (1)

Where:

$F$ - Axial force, measured in newtons.

$D$ - Cross-section diameter, measured in meters.

Please notice that axial force is the weight of the man hanging from wire.

If we know that $F = 800\,N$ and $D = 0.002\,m$ , then the axial stress experimented by the titanium wire is:

$\sigma = \frac{4\cdot (800\,N)}{\pi\cdot (0.002\,m)^{2}}$

$\sigma \approx 2.546\times 10^{8}\,Pa$

Since stress is greater than ultimate strength, the wire will break.

3 0

3 years ago

(X^2-2x+1)/x^2-x how do you simplify and divide this rational expression

Georgia [21]

$\frac{X^2-2x+1}{x^2-x} = \frac{(x-1)(x-1)}{x(x-1)} = \frac{x-1}{x}$

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3 years ago

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Softa [21]

Answer:

CAB = 30.71 BCA = 90 ABC = 59.29

Step-by-step explanation:

BCA = 90

9x + 6 + 5x = 90

14 x = 90-6 = 84

x = 43/7

(43/7 ) * 5 = 30.71

90 - 30.71 = 59.29

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3 years ago

The "sum" of two numbers is: A the result when both numbers are added together B the result when the first number is subtracted

Irina-Kira [14]

Answer:

A the result when both numbers are added together

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kati45 [8]

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<em>X</em><em>. </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>f(</em><em>x)</em>

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3 -4

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(<em>0</em><em>,</em><em>-</em><em>1</em><em>0</em><em>)</em><em>,</em><em>(</em><em>3</em><em>,</em><em>-</em><em>4</em><em>)</em><em>,</em><em>(</em><em>5</em><em>,</em><em>0</em><em>)</em><em>,</em><em>(</em><em>6</em><em>,</em><em>2</em><em>)</em>

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3 years ago

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