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Keith_Richards [23]
3 years ago
6

Realiza tres ejemplos de probabilidad subjetiva

Mathematics
1 answer:
Lemur [1.5K]3 years ago
5 0

ojala te sirva

es niño o niña?: La abuela de un bebe que esta por nacer asegura que el futuro bebé será una niña y no un niño, la abuela se basa en los antojos de la madre, la forma del estómago de la madre y otras características que ella ha podido observar durante el embarazo.

te comparto imagenes ok

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(sinB+1)(cosBtanB-1)
Karo-lina-s [1.5K]
Here you go!!! I hope this helps

6 0
2 years ago
Is a survey of the guests about their preference of food at a party an observational study or experimental study? If it is an ex
Andreas93 [3]

Answer:

The study is an observational study.

Step-by-step explanation:

Observational study: In research methods, the term "observational study" is determined as one of the different studies that are being conducted by the researchers to observe or study the effects of a specific risk factor, treatment, diagnostic test, or some other intervention in the absence of an effort to change which participants are being exposed and which is not being exposed to it.

Types: Cohort study and case-control study.

In the question above, the given statement represents the observational study.

6 0
3 years ago
Jasmine believe the lengths 7 in 12 in and 20 inch will form a triangle is Jasmine correct use mathematics or words to explain y
madreJ [45]

Answer:

7 in 12 30 inch jasmine correct is triangle

7 0
1 year ago
x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
What is 3x squared-12x=0
lubasha [3.4K]

x=0 or x=4

just factorize basically

cancels the x’s so it’d be 3x-12=0 and from that x=4

3 0
3 years ago
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