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4 years ago

Calcular el largo de la hipotenusa

Mathematics

1 answer:

patriot [66]4 years ago

7 0

You didn’t provide the picture

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Trygg has 3/4 package of marigold seeds. He plants 1/6 of those seeds in his garden as and divides the rest equally into 10 flow

stepan [7]

He has 3/4 package and plants 1/6 of seeds.

3/4 * 1/6 = 1/8

He divides the rest equally into 10 flowerpots. What is the rest? In order to know what "the rest" is, you must subtract 1/8 from 3/4. Find the common denominator of 4 and 8 which is 8. Multiple the numerator 3 * 2= 6 with a denominator of 8.

3/4 - 1/8 = 6/8 -1/8
= 5/8

5/8 is left to be divided equally into 10 flowerpots.

5/8 ÷ 10/1
= 5/8 * 1/10
= 5/80
= 1/16

3 0

3 years ago

What is the best estimate for 8.3 x 4.9?

sammy [17]

Answer:

40.67

Step-by-step explanation:

I calculated it

6 0

3 years ago

Solve each quadratic equation by factoring and using the zero product property.

vitfil [10]

Answer:

x=7 multiplicity of 2

Step-by-step explanation:

14x - 49 = x^2

Subtract x^2 from each side

-x^2 +14x - 49 = x^2-x^2

-x^2 +14x - 49 = 0

Multiply by -1

x^2 -14x +49 =0

What 2 numbers multiply together to give you 49 and add together to give you -14

7*-7 = 49

-7+-7 = -14

(x-7) (x-7) = 0

Using the zero product property

x-7 = 0 x-7 =0

x-7+7= 0+7 x-7+7 =0+7

x =7 x=7

4 0

3 years ago

Read 2 more answers

Given f(x)=x^2-2 and g(x)= the square root of x-7, identify the composite function of g(f(x)) and it's correct domain

Ksenya-84 [330]

$g(f(x))=\sqrt{x^2-2-7}=\sqrt{x^2-9}\\\\
D:x^2-9\geq0\\
D:(x-3)(x+3)\geq0\\
D:x\in(-\infty,-3]\cup[3,\infty)$

7 0

3 years ago

In how many ways can 2 red, 2 black, 3 white and 2 blue balls be selected from 4 red, 3 black, 4 white and 8 blue balls? In how

Montano1993 [528]

From the total pool of colored balls, one can choose 2 reds, 2 blacks, 3 whites, and 2 blues in

$\dbinom42\cdot\dbinom32\cdot\dbinom43\cdot\dbinom82=6\cdot3\cdot4\cdot28=2016$

ways.

I'm assuming no ball of the same color is distinguishable from any other ball of the same color. So when I'm considering the possible arrangements, if I had lined up the ball as

red1 - black - red2 - ...

then this would be no different that

red2 - black - red1 - ...

So I now have 9 balls to arrange, which means there are $9!=362,880$ total possible permutations of them. But order among distinct colors is assumed to not matter. This means I have to divide the total number of permutations by the number of ways I could permute balls of the same color. Then there would be a total of

$\dfrac{9!}{2!\cdot2!\cdot3!\cdot2!}=7,560$

ways of arranging the balls I had selected.

5 0

3 years ago