The given equation is:
![y= \sqrt{x+3}](https://tex.z-dn.net/?f=y%3D%20%5Csqrt%7Bx%2B3%7D%20)
We have to find, which of the given set of parametric equations given in the options, result in the above equation:
The correct answer would be option A.
The equations in option A are:
![x(t) = 5t \\ y(t)= \sqrt{5t+3}](https://tex.z-dn.net/?f=x%28t%29%20%3D%205t%20%5C%5C%20%0Ay%28t%29%3D%20%5Csqrt%7B5t%2B3%7D%20)
From first equation we can see that 5t is equal to x. Using the value of 5th in second equation, we get the equation as:
Therefore, the correct answer is option A
Answer:
c)
Step-by-step explanation:
![- \frac{7}{ - f} \: is \: equal \: to \: \frac{7}{f}](https://tex.z-dn.net/?f=%20%20-%20%5Cfrac%7B7%7D%7B%20-%20f%7D%20%5C%3A%20is%20%5C%3A%20equal%20%5C%3A%20to%20%5C%3A%20%20%5Cfrac%7B7%7D%7Bf%7D%20)
![so \: the \: answer \: is \: none \: of \: the \: above](https://tex.z-dn.net/?f=so%20%5C%3A%20the%20%5C%3A%20answer%20%5C%3A%20is%20%5C%3A%20none%20%5C%3A%20of%20%5C%3A%20the%20%5C%3A%20above)
Answer:
d
Step-by-step explanation:
<h3>Answer: Step-by-step explanation:
You have to make an addition with the individual times: 56.25+59.89+58.55+55.4=230.17 seconds. Now you should to convert it into a minutes and seconds. 1 minute= 60 seconds
2 minute= 120 seconds
3minute= 180 seconds
4minute= 240 seconds
In this way you they have 3 minutes and the remainder is 50 seconds.
So, the time for the team is 3 minutes and 50.17 seconds.</h3>
1) |−11| = 11, therefore Peter is at a distance of 11 feet
2) Jimmy, because each of the two points is fraction 5 over 8 unit away from 0
3) 36 + 28=64 4x4=36+4x7=28 36+28=64
7+9=16 4x16=64