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RSB [31]
3 years ago
9

The two conditional relative frequency tables show the results of a neighborhood survey on the number and types of gardens in th

e community.
Which table could be used to answer the question "Assuming someone has a flower garden, what is the probability they also have a vegetable garden?"

1) Table A, because the given condition is that the person has a flower garden.

2) Table A, because the given condition is that the person has a vegetable garden.

3) Table B, because the given condition is that the person has a flower garden.

4) Table B, because the given condition is that the person has a vegetable garden.

Mathematics
2 answers:
Basile [38]3 years ago
7 0

C.

Because the given condition required to have a flower garden first and then the probability of having a vegetable garden is calculated.

n200080 [17]3 years ago
6 0

Answer: 3) Table B, because the given condition is that the person has a flower garden.

Step-by-step explanation:

In Table A, there are frequencies by column .

The columns of the table are "Vegetable Garden" and "No Vegetable Garden".

It means if we assume some one as a Vegetable Garden or No Vegetable Garden as initial condition, then Table A works.

In Table B, there are frequencies by rows .

The columns of the table are "Flower Garden" and "No Flower Garden".

It means if we assume some one as a Flower Garden or No Flower Garden as initial condition ,then Table B works.

Hence, Table B could be used to answer the given question  because the given condition is that the person has a flower garden.

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Step-by-step explanation:

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3 years ago
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-10(-2)+y=4

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4 years ago
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A rectangular plot of farmland will be bounded on one side by a river and on the other three sides by a​ single-strand electric
larisa86 [58]

Answer:

525 x 1,050

A = 551,250 m²

Step-by-step explanation:

Let 'L' be the length parallel to the river and 'S' be the length of each of the other two sides.

The length of  the three sides is given by:

2S+L=2,100\\ L=2100-2S

The area of the rectangular plot is given by:

A=S*L\\A=S(2100-2S)\\A=2100 S -2S^2

The value of 'S' for which the area's derivate is zero, yields the maximum total area:

\frac{dA(S)}{dS}=\frac{d(2100 S -2S^2)}{dS}\\0= 2100 - 4S\\S=525

Solving for 'L':

L=2100-(2*525)\\L=1,050

The largest area enclosed is given by dimension of 525 m x 1,050 and is:

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4 years ago
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3 years ago
Which of the following is an extraneous solution of (45-3x)^1/2=x-9?
Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

3 0
4 years ago
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