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Marrrta [24]
3 years ago
6

What is the equation of a line perpendicular to the line 7x+4y=15+2x and passes through the point (0.5,0.5)?

Mathematics
1 answer:
Rzqust [24]3 years ago
8 0
4y=-5x+15
y=-5/4x+15/4
y-1/2=4/5(x-1/2)
y-1/2=4/5x-2/5
y-5/10=4/5x-4/10
y=4/5x+1/10
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If you had $350 and you spent the following
Olin [163]

Answer:

B.) $58

Step-by-step explanation:

350-89-18-27-38-120 = 58

6 0
3 years ago
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Solve.<br><br> The answer must be a fraction. Solve by substituting.
maw [93]

Answer: x = -14/5

Step-by-step explanation: We shall begin by expanding the brackets for both sides of the equation

-2/3 (x + 2) = 1/6 (x + 6)

(-2x/3) -4/3 = (x/6) + 1

By collecting like terms we now have

(-2x/3) - (x/6) = 1 + 4/3

(-4x - x)/6 = 7/3

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By cross multiplication we now have

-5x (3) = 7 (6)

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x = -(42/15) {simplify further by dividing the RHS by 3}

x = -14/5

Therefore x equals, minus fourteen over five (-14/5)

4 0
3 years ago
A boat travels upstream for 48 miles in 3 hours and returns in 2 hours traveling downstream in a river. What is the rate of the
alekssr [168]

Answer:

20 mph and 4 mph

Step-by-step explanation:

GIVEN: A boat travels upstream for 48 miles in 3 hours and returns in 2 hours traveling downstream in a river.

TO FIND: What is the rate of the boat in still water and the rate of the current.

SOLUTION:

Let the speed of boat in still water be s and speed of current be a.

\therefore speed of water in upstream =s+a

  speed of water in downstream =s-a

As  speed=\frac{distance}{time}

s+a=\frac{48}{3}=16

s-a=\frac{48}{2}=24

Solving both we get

s=20\text{ mph}

a=4\text{ mph}

Hence speed of boat in still water and rate of current is 20mph and 4mph respectively.

3 0
4 years ago
I need help almost ASAP!!! 1-5
alekssr [168]
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8 0
3 years ago
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Use binomial expansion to solve each exercise. (a) Find the coefficient of xy19 in (3x − 2y) 20.(b) Give a formula for the coeff
pishuonlain [190]

9514 1404 393

Answer:

  (a) -29,884,416

  (b) C(n,(n -k)/2) . . . where C(n,k) = n!/(k!(n-k)!) and k ∈ ℕ

Step-by-step explanation:

(a) The coefficient of the k-th term of the expansion is ...

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For k=19, this is ...

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The coefficient of the term is -29,884,416.

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(b) The p-th term of the expansion of (x +1/x)^n is ...

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For some exponent k of x, the value of p will be ...

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You will notice that there will only be a term x^k for k having the same parity as n.

5 0
3 years ago
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