Answer:
f(g(x)) = x² - 5x +4
Step-by-step explanation:
<u><em>Explanation</em></u>
Given that the functions
f(x) = x² + 3 x and g(x) = x-4
f(g(x)) = f(x -4) (∵ g(x) = x-4)
= (x-4)² + 3(x-4)
= x² - 2(4)x + 4² + 3x -12
= x² - 8 x + 16 + 3x -12
= x² - 5x +4
∴ f(g(x)) = x² - 5x +4
Answer: 26xy-5
(x3y6)-2 + (x2y4)-3
(18xy)-2 + (8xy)-3
18xy -2 + 8xy - 3
26xy -5
Answer:
see below
Step-by-step explanation:
3 ^ ( 6/5)
The base a is 3
The power is 6 which is b
the root is 5 which is c
![\sqrt[5]{3^6}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B3%5E6%7D)
Answer:
a) 3.6
b) 1.897
c)0.0273
d) 0.9727
Step-by-step explanation:
Rabies has a rare occurrence and we can assume that events are independent. So, X the count of rabies cases reported in a given week is a Poisson random variable with μ=3.6.
a)
The mean of a Poisson random variable X is μ.
mean=E(X)=μ=3.6.
b)
The standard deviation of a Poisson random variable X is √μ.
standard deviation=S.D(X)=√μ=√3.6=1.897.
c)
The probability for Poisson random variable X can be calculated as
P(X=x)=(e^-μ)(μ^x)/x!
where x=0,1,2,3,...
So,
P(no case of rabies)=P(X=0)=e^-3.6(3.6^0)/0!
P(no case of rabies)=P(X=0)=0.0273.
d)
P(at least one case of rabies)=P(X≥1)=1-P(X<1)=1-P(X=0)
P(at least one case of rabies)=1-0.0273=0.9727
