I hope this helps you
(-3).x+2. (-3)
-3x-6
In this problem, we can imagine that all the points
connect to form a triangle. The three point or vertices are located on the
pitcher mount, the home plate and where the outfielder catches the ball. So in
this case we are given two sides of the triangle and the angle in between the
two sides.
<span>With the following conditions, we can use the cosine law
to solve for the unknown 3rd side. The formula is:</span>
c^2 = a^2 + b^2 – 2 a b cos θ
Where,
a = 60.5 ft
b = 195 ft
θ = 32°
Substituting the given values:
c^2 = (60.5)^2 + (195)^2 – 2 (60.5) (195) cos 32
c^2 = 3660.25 + 38025 – 20009.7
c^2 = 21,675.56
c = 147.23 ft
<span>Therefore the outfielder throws the ball at a distance of
147.23 ft towards the home plate.</span>
So the ratios are 5:5 and 3:5 so the fractions are 5/10 (1/2) for 7th grade and 5/8 for 8th grade
55 if you mean one half
5500 if you mean 50 times 110
60 if you mean 50 from 110
Answer:
10 strawberries
Step-by-step explanation:
If Mike can pick 50 strawberries in 5 minutes then it is safe to assume that for 1 minute, Mike can pick 10 strawberries since you divide 50 by 5 in which Mike can pick a strawberry for every 6 seconds.
