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olasank [31]
3 years ago
6

The perimeter of a rectangular room is 60 feet. Let x be the width of the room (in feet) and let y be the length of the room (in

feet). Select all of the equations below that could model this situation.
2(x+y)=60
2x+2y=60
x+2y=60
2x+y=60
x+y=60
Mathematics
1 answer:
8090 [49]3 years ago
7 0
8187+88282

Explaination: wjwnbenehehw
You might be interested in
Beverly drew the line AB shown below. She then constructed line DC which is the perpendicular bisector of AB.
earnstyle [38]

Answer:

D

Line segments are congruent due to the side-angle-side congruence postulate.

Step-by-step explanation:

DC is the perpendicular bisector of line AB, this mean that DC divides AB at 90 degrees into two equal parts at point E. Hence:

AE = BE

Also DE ≅ DE (reflexive property of congruence)

Also ∠AED = ∠BED = 90° (perpendicular bisector)

We can therefore say that triangle AED and triangle BED are congruent according to the side-angle-side congruence theorem. Therefore line AD = line BD

5 0
2 years ago
Jerry says I've got my money in a great account that compounds interest monthly. The equation y=388 (1.008) represents how much
zheka24 [161]

Answer:

(a)His monthly Interest Rate=0.8%

(b)Annual Interest Rate = 9.6%

(c)500(1.008)^m

Step-by-step explanation:

For a Principal P invested at a yearly rate r, compounded m times in t years

Amount at Compound Interest= P(1+\frac{r}{m})^{mt}

Comparing with Jerry's equation y=388 (1.008)

(a)His monthly Interest Rate= 0.008=0.8%

(b)Annual Interest Rate= Monthly Interest Rate X 12 =0.8 X 12 = 9.6%

(c)If I invest $500 at the same rate of return,

Total Money after m months

= P(1+\frac{r}{m})^{mt}=500(1+0.008)^{m}=500(1.008)^m

7 0
3 years ago
. In a study of air-bag effectiveness it was found that in 821 crashes of midsize cars equipped with air bags, 46 of the crashes
jok3333 [9.3K]

Answer:

P(X ≤ 46 | X~B(821, 0.078)) = 0.00885745584

0.00885... < 0.01

The test statistic of 46 is significant

There is sufficient evidence to reject H₀ and accept H₁

Air bags are more effective as protection than safety belts

Step-by-step explanation:

821 crashes

46 hospitalisations where car has air bags

7.8% or 0.078 probability of hospitalisations in cars with automatic safety belts

α = 0.01 or 1% ← level of significance

One-tailed test

We are testing whether hospitalisations in cars with air bags are less likely than in a car with automatic safety belts;

The likelihood of hospitalisation in a car with automatic safety belts, we are told, is 7.8% or 0.078;

So we are testing if hospitalisations in cars with air bags is less than 0.078;

So, firstly:

Let X be the continuous random variable, the number of hospitalisations from a car crash with equipped air bags

X~B(821, 0.078)

Null hypothesis (H₀): p = 0.078

Alternative hypothesis (H₁): p < 0.078

According to the information, we reject H₀ if:

P(X ≤ 46 | X~B(821, 0.078)) < 0.01

To find P(X ≤ 46) or equally P(X < 47), it could be quite long-winded to do manually for this particular scenario;

If you are interested, the manual process involves using the formula for every value of x up to and including 46, i.e. x = 0, x = 1, x = 2, etc. until x = 46, the formula is:

P(X = r) = nCr * p^{r}  * (1 - p)^{n - r}

You can find binomial distribution calculators online, where you input n (i.e. the number of trials or 821 in this case), probability (i.e. 0.078) and the test statistic (i.e. 46), it does it all for you, which gives:

P(X ≤ 46 | X~B(821, 0.078)) = 0.00885745584

Now, we need to consider if the condition for rejecting H₀ is met and recognise that:

0.00885... < 0.01

There is sufficient evidence to reject H₀ and accept H₁.

To explain what this means:

The test statistic of 46 is significant according to the 1% significance level, meaning the likelihood that only 46 hospitalisations are seen in car crashes with air bags in the car as compared to the expected number in car crashes with automatic safety belts is very unlikely, less than 1%, to be simply down to chance;

In other words, there is 99%+ probability that the lower number of hospitalisations in car crashes with air bags is due to some reason, such as air bags being more effective as a protective implement than the safety belts in car crashes.

5 0
3 years ago
Is this a proportional or nonproportional linear relationship?
BlackZzzverrR [31]

Answer:

Linear

Step-by-step explanation:

The numbers add by 4 it’s not scrambled

3 0
2 years ago
Read 2 more answers
What is the standard deviation of the data set?
tester [92]
B is the answer to the question 6.8

7 0
3 years ago
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