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3 years ago

6

The perimeter of a rectangular room is 60 feet. Let x be the width of the room (in feet) and let y be the length of the room (in

feet). Select all of the equations below that could model this situation.
2(x+y)=60
2x+2y=60
x+2y=60
2x+y=60
x+y=60

1 answer:

8090 [49]3 years ago

7 0

8187+88282

Explaination: wjwnbenehehw

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95 points <br><br> Simplify (4^9/4^3)^5 Show your work for full credit

dexar [7]

Answer:

$4^{30}$

Step-by-step explanation:

$(4^9/4^3)^5=$
$(4^{9-3})^5=$
$(4^6)^5=$
$4^{6*5}=$
$4^{30}$

3 0

2 years ago

Read 2 more answers

Given z=4+3i evaluate z

DerKrebs [107]

Answer:

5

Step-by-step explanation:

Assuming we want to evaluate |z|, given that, z=4+3i.

Then, by definition of modulus,

$|x + yi| = \sqrt{ {x}^{2} + {y}^{2} }$

$|4+ 3i| = \sqrt{ {4}^{2} + {3}^{2} }$

$|4+ 3i| = \sqrt{ 16+ 9 } \\ |4+ 3i| = \sqrt{25 } \\ |4+ 3i| = 5$

Therefore the modulus be of the given complex number is 5 units

5 0

3 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago

Ms. Jones had $40 to purchase groceries. She bought 4 packs of rice and 3 boxes of granola bars. The packs of rice cost $1.09 ea

Nesterboy [21]

Answer:

so to know full price of granola bars and rice packs; you would multiply 1.09 × 4 for the rice which you get 4.36 then for granola bars you do 4.29 × 3 and you get 12.87 then you add 12.87 + 4.36 = 17.23 then you subtract this from the $$ Mr.Jones has which is 40 so its 40-17.23 and you get 22.77

7 0

3 years ago

Help me please <br>im also very tried right now so please help

Molodets [167]

I’m pretty sure it’s the third one sorry if i’m wrong

5 0

2 years ago