3 years ago

How to solve this? 4cos(4x)sin(10x)

Mathematics

1 answer:

kodGreya [7K]3 years ago

5 0

Answer:

2/5 or 0.4

Step-by-step explanation:

You might be interested in

4 4/5 x 3 2/6 I don’t understand this pls help

klasskru [66]

Answer:

change to improper fraction

24/5 × 20/6=16 (you cross multiply)

4 0

2 years ago

Read 2 more answers

(N * 3) + 6 - (n * 2) = n + 3 what is value of n

GalinKa [24]

(n*3)+6-(n*2)=n+3
3n+6-2n=n+3
3n-2n-n=3-6 every n on the left and free numbers on the right
0=-3
contradiction, there are no solution

7 0

3 years ago

Read 2 more answers

Solve this problem: –282 – (+1,017) = ?

klio [65]

The answer is -1,299

4 0

3 years ago

Read 2 more answers

The students begin to play games. Each game takes 10 minutes

zvonat [6]

What are you looking for?

4 0

3 years ago

Pumps A, B, and C operate at their respective constant rates. Pumps A and B, operating simultaneously, can fill a certain tank i

shepuryov [24]

Answer:D) 1 hr

Step-by-step explanation:

Given

Pump A and B can fill tank in $\frac{6}{5} hr$

Pump A and C can fill tank in $\frac{3}{2} hr$

Pump B and C can fill tank in $2 hr$

Let A be the total hr taken A therefore rate of $A=\frac{1}{A} /hr$

Let B be the total hr taken B therefore rate of $B=\frac{1}{B} /hr$

Let C be the total hr taken C therefore rate of $C=\frac{1}{C} /hr$

$\frac{1}{A}+\frac{1}{B}=\frac{5}{6}$ -----1

$\frac{1}{B}+\frac{1}{C}=\frac{1}{2}$ -----2

$\frac{1}{A}+\frac{1}{C}=\frac{2}{3}$ -----3

Adding 1,2 & 3

$2(\frac{1}{A}+\frac{1}{B}+\frac{1}{C})=\frac{5}{6}+\frac{1}{2}+\frac{2}{3}$

$\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=\frac{2}{2}$

$\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=1$

thus time taken by A,B and C combined is 1 hr

7 0

2 years ago