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3 years ago

How to solve this? 4cos(4x)sin(10x)

Mathematics

1 answer:

kodGreya [7K]3 years ago

5 0

Answer:

2/5 or 0.4

Step-by-step explanation:

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The circumference of a circle is 10 cm. What is the Radius of the circle

WITCHER [35]

Answer:

The radius is 5

Step-by-step explanation:

The radius is half the circumference. Therefore, 10 ÷ 2 = 5.

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3 years ago

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Angelina has a fish tank in the shape of a rectangular prism. The fish tank is 20 inches long, 7 inches wide, and 12 inches tall

igor_vitrenko [27]

Answer: 1680 inches cubed

Step-by-step explanation:

Volume = Length x Width x Height

V = 20 x 7 x 12

V = 140 x 12

V = 1680 inches cubed

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3 years ago

12x(x+2)−5(2x−1) find the equation

ankoles [38]

Perform the indicated multiplications...

12x*x+12x*2-5*2x-5*(-1)

12x^2+24x-10x+5 combine like terms

12x^2+14x+5

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3 years ago

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What is the answer to (−t/3)^2?

Sloan [31]

Answer:

Simplify the expression.

t^/9

Step-by-step explanation:

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4 years ago

I need help on 17 and 23 pls

ludmilkaskok [199]

Question # 17 Solution

Answer:

$x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}$

Step-by-step Explanation:

The given expression

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

And we have to solve for x₁

So,

Lets solve for x₁.

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Multiply both sides by x₂ - x₁

$m(x_{2}-x_{1})= (x_{2}-x_{1})\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m(x_{2}-x_{1})= (y_{2}-y_{1})$

$mx_{2}-mx_{1}= (y_{2}-y_{1})$

$-mx_{1}= y_{2}-y_{1}-mx_{2}$

Divide both sides by -m

$\frac{-mx_{1}}{-m}= \frac{y_{2}-y_{1}-mx_{2}}{-m}$

$x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}$

Therefore, $x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}$

Question # 23 Solution

Answer:

$n= \frac{bx}{-b + x}$

Step-by-step Explanation:

The given expression

$\frac{nx}{b}-x=x$

And we have to solve for n

So,

Let's solve for n.

$\frac{nx}{b}-x=x$

Multiply both sides by b.

$-bn + nx = bx$

Factor out n.

$n(-b + x)= bx$

Divide both sides by -b + x.

$\frac{n(-b + x)}{-b + x}= \frac{bx}{-b + x}$

$n= \frac{bx}{-b + x}$

Therefore, $n= \frac{bx}{-b + x}$

Keywords: solution, equation

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6 0

4 years ago