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3 years ago

Kim has a rope that is meter long, she wants to cut it into 5 places, Each piece must be the same size.

Mathematics

1 answer:

storchak [24]3 years ago

3 0

Answer:

1/5 meter per piece

Step-by-step explanation:

Divide this 1-meter-long rope by 5:

1 meter

--------------- = 1/5 meter per piece, or 200 mm

5 pieces

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An angle measures 80.2° less than the measure of its complementary angle. What is the measure of each angle

creativ13 [48]

Answer:

9.8 degree + 80.2 degree

As both need to add up to 90 degree to be complementary.

Step-by-step explanation:

Complementary angle means adds up to 90 degree.

Therefore- 90-80.2 = 9.8 degree

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2 years ago

What value for x makes the sentence true? 4X-4 = 20

skad [1K]

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3 years ago

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Use the position equation given below, where s represents the height of the object (in feet),

mariarad [96]

The answers to the questions are

The mathematical model is given as s = −16t2 + 1054
The height after 4.5 seconds is 730 feet

the time it would take to strike the ground is 8.11 seconds.

<h3>How to solve for the position of the object</h3>

The mathematical model of this problem would be written as

s = −16t2 + v0t + s0

s0 = 1054

then we would have

s = −16t2 + 1054

b. after 4.5 seconds the height is going to be

s = −16t2 + 1054

= −16(4.5)² + 1054

= -16 * 20.25 + 1054

= 730

C. the time that it takes to strike the ground

s = −16t² + 1054

= 16t² = 1054

t² = 1054/16

= 65.88

t = √65.88

t = 8.11

Hence the time it would take to strike the ground is 8.11 seconds.

Read more on velocity here:

brainly.com/question/4931057

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1 year ago

Write down the explicit solution for each of the following: a) x’=t–sin(t); x(0)=1

Kay [80]

Answer:

a) x=(t^2)/2+cos(t), b) x=2+3e^(-2t), c) x=(1/2)sin(2t)

Step-by-step explanation:

Let's solve by separating variables:

$x'=\frac{dx}{dt}$

a) x’=t–sin(t), x(0)=1

$dx=(t-sint)dt$

Apply integral both sides:

$\int {} \, dx=\int {(t-sint)} \, dt\\\\x=\frac{t^2}{2}+cost +k$

where k is a constant due to integration. With x(0)=1, substitute:

$1=0+cos0+k\\\\1=1+k\\k=0$

Finally:

$x=\frac{t^2}{2} +cos(t)$

b) x’+2x=4; x(0)=5

$dx=(4-2x)dt\\\\\frac{dx}{4-2x}=dt \\\\\int {\frac{dx}{4-2x}}= \int {dt}\\$

Completing the integral:

$-\frac{1}{2} \int{\frac{(-2)dx}{4-2x}}= \int {dt}$

Solving the operator:

$-\frac{1}{2}ln(4-2x)=t+k$

Using algebra, it becomes explicit:

$x=2+ke^{-2t}$

With x(0)=5, substitute:

$5=2+ke^{-2(0)}=2+k(1)\\\\k=3$

Finally:

$x=2+3e^{-2t}$

c) x’’+4x=0; x(0)=0; x’(0)=1

Let $x=e^{mt}$ be the solution for the equation, then:

$x'=me^{mt}\\x''=m^{2}e^{mt}$

Substituting these equations in c)

$m^{2}e^{mt}+4(e^{mt})=0\\\\m^{2}+4=0\\\\m^{2}=-4\\\\m=2i$

This becomes the solution m=α±βi where α=0 and β=2

$x=e^{\alpha t}[Asin\beta t+Bcos\beta t]\\\\x=e^{0}[Asin((2)t)+Bcos((2)t)]\\\\x=Asin((2)t)+Bcos((2)t)$

Where A and B are constants. With x(0)=0; x’(0)=1:

$x=Asin(2t)+Bcos(2t)\\\\x'=2Acos(2t)-2Bsin(2t)\\\\0=Asin(2(0))+Bcos(2(0))\\\\0=0+B(1)\\\\B=0\\\\1=2Acos(2(0))\\\\1=2A\\\\A=\frac{1}{2}$

Finally:

$x=\frac{1}{2} sin(2t)$

7 0

3 years ago

find the volume of a right circular cone that has a height of 14.7 ft and a base with a circumference of 13 ft

Doss [256]

Answer:

Volume of the cone =650.06 cubic feet

Step-by-step explanation:

Height of the cone= 14.7 feet

Circumference= 13 feet

Radius = 13/2 = 6.5 feet

Volume of the Cone:

$=\pi r^2\frac{h}{3}$

As, $\pi =\frac{22}{7}=3.14$

Putting the values in the formula:

Volume of the cone is :

$=3.14*(6.5*6.5)*\frac{14.7}{3} \\\\=3.14*(6.5*6.5)*4.9\\\\=3.14*42.25*4.9\\\\=3.14*207.03\\\\=650.06feet^3$

Volume of the cone is 650.06 cubic feet

8 0

3 years ago