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3 years ago

Guys i need your help!! what is 600x300

Mathematics

1 answer:

PtichkaEL [24]3 years ago

4 0

Answer: 180000

6 multiplied by 3 is 18 and just add 4 zeros because they’re the total zeros present in the question

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taurus [48]

Answer:

Step-by-step explanation:

49 - 3 + 72/2

= 46 + 36

= 82

7 0

3 years ago

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Please help -HA -LL -HL -LA

yulyashka [42]

Answer:

Step-by-step explanation:

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3 years ago

What is the range of the equation

a_sh-v [17]

The range of the equation is $y>2$

Explanation:

The given equation is $y=2(4)^{x+3}+2$

We need to determine the range of the equation.

Range:

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

$y=2 \cdot 4^{x+3}+2$

This can be written as $y=2^{1+2(x+3)}+2$

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

$x=2^{1+2(y+3)}+2$

Solving for y, we get;

$x-2=2^{1+2(y+3)}$

Applying the log rule, if f(x) = g(x) then $\ln (f(x))=\ln (g(x))$ , then, we get;

$\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)$

Simplifying, we get;

$(1+2(y+3)) \ln (2)=\ln (x-2)$

Dividing both sides by $\ln (2)$ , we have;

$2 y+7=\frac{\ln (x-2)}{\ln (2)}$

Subtracting 7 from both sides of the equation, we have;

$2 y=\frac{\ln (x-2)}{\ln (2)}-7$

Dividing both sides by 2, we get;

$y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}$

Let us find the positive values for logs.

Thus, we have,;

$x-2>0$

$x>2$

The function domain is $x>2$

By combining the intervals, the range becomes $y>2$

Hence, the range of the equation is $y>2$

7 0

4 years ago

Solve for x. please helppp! it’s the end of the grading period

Lynna [10]

Answer:

x=4

Step-by-step explanation:

16 = 4x

16/4 = x

4 = x

6 0

3 years ago

Drag the slider to see the number of water lilies in

Misha Larkins [42]

Answer:

0 days:

1 day:

2 days:

3 days:

4 days:

5 days:

Step-by-step explanation:

6 0

3 years ago

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