Cute one!
<span>
</span>Summarizing:
<span>sec(acot(tan(asin(sin(pi/3)))) .... use asin(sin(x))=x
</span>=sec(acot(tan(pi/3)))
=sec(acot(sqrt(3))) ......... use acot(x)=atan(1/x)
=sec(atan(1/sqrt(3)))
=sec(atan(sqrt(3)/3)) .... evaluate atan(sqrt(3)/3), use unit circle
=sec(pi/6)
=1/cos(pi/6)...... evaluate cos(pi/6), use unit circle
=1/(sqrt(3)/2)
=2/sqrt(3) .... now rationalize
=2sqrt(3)/3
The GCF of 7 and 14a is 7, so the factors are:-
7(1 + 2a)
<span>Solving for the slope using points ( (−4, 15), (0, 5)</span>
M = ( 15 – 5) / ( -4 – 0) = -5 / 2
Solving for b
<span>
Y = mx + b</span>
5 = 0(-5/2) + b
B = 5
So the linear function is
<span>Y = (-5/2) x + 5</span>
Answer:
3rd option
Step-by-step explanation:
The equation of a line in point- slope form is
y - y₁ = m(x - x₁)
where m is the slope and (x₁, y₁ ) a point on the line
Here m = - 2 and (x₁, y₁ ) = 4. - 6 ) , then
y - (- 6) = - 2(x - 4) , that is
y + 6 = - 2(x - 4)
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