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nadya68 [22]
3 years ago
5

4(2x + 3) in the simplest form

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
3 0

Answer: 8x+12

Step-by-step explanation:

We can use the Distributive Property to get it in it's simplest form

4(2x+3)

(4)(2x)+(4)(3)

8x+12

Oksana_A [137]3 years ago
3 0

Answer:

8x + 12

Step-by-step explanation:

<em>S</em><em>imply</em><em> </em><em>solve</em><em> </em><em>the</em><em> </em><em>brackets</em><em>.</em>

<em>4(2x + 3) \\ 8x + 12</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em>

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8 0
3 years ago
What is the standard form of the equation of a line for which the length of the normal segment to the origin is 8 and the normal
jeka57 [31]
Slope of line = tan(120) = -tan(60) = - &radic;3
Distance from origin = 8

Let equation be Ax+By+C=0
then -A/B=-&radic;3, or
B=A/&radic;3.
Equation becomes
Ax+(A/&radic;3)y+C=0

Knowing that line is 8 units from origin, apply distance formula
8=abs((Ax+(A/&radic;3)y+C)/sqrt(A^2+(A/&radic;3)^2))
Substitute coordinates of origin (x,y)=(0,0)  =>
8=abs(C/sqrt(A^2+A^2/3))
Let A=1 (or any other arbitrary finite value)
solve for positive solution of C
8=C/&radic;(4/3) => C=8*2/&radic;3 = (16/3)&radic;3

Therefore one solution is
x+(1/&radic;3)+(16/3)&radic;3=0
or equivalently
&radic;3 x + y + 16 = 0

Check:
slope = -1/&radic;3  .....ok
distance from origin
= (&radic;3 * 0 + 0 + 16)/(sqrt(&radic;3)^2+1^2)
=16/2
=8  ok.

Similarly C=-16 will satisfy the given conditions.

Answer  The required equations are
&radic;3 x + y = &pm; 16 
in standard form.

You can conveniently convert to point-slope form if you wish.




4 0
3 years ago
One and two third minus two and two third
jeyben [28]

Answer:

1 \frac{2}{3} - 2\frac{2}{3}  = -1

Step-by-step explanation:

1\frac{2}{3} - 2 \frac{2}{3\\} \\\\\frac{5}{3} - \frac{8}{3} = \frac{-3}{3} \\ \\\frac{-3}{3} = -1

Hope this helps! :)

3 0
3 years ago
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