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3 years ago

Helpp

Mathematics

1 answer:

timama [110]3 years ago

7 0

Answer:

X² + 1 (B)

Step-by-step explanation:

Y = X² + 1

x =2

then X² + 1 = y

(2)² + 1 = 5 (that is your Y)

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On an alien planet with no atmosphere, acceleration due to gravity is given by g = 12m/s^2. A cannonball is launched from the or

almond37 [142]

Answer:

a) $\vec r (t) = \left[(90\cdot \cos \theta)\cdot t \right]\cdot i + \left[(90\cdot \sin \theta)\cdot t -6\cdot t^{2} \right]\cdot j$ , b) $\theta = \frac{\pi}{4}$ , c) $y_{max} = 84.375\,m$ , $t = 3.75\,s$ .

Step-by-step explanation:

a) The function in terms of time and the inital angle measured from the horizontal is:

$\vec r (t) = [(v_{o}\cdot \cos \theta)\cdot t]\cdot i + \left[(v_{o}\cdot \sin \theta)\cdot t -\frac{1}{2}\cdot g \cdot t^{2} \right]\cdot j$

The particular expression for the cannonball is:

$\vec r (t) = \left[(90\cdot \cos \theta)\cdot t \right]\cdot i + \left[(90\cdot \sin \theta)\cdot t -6\cdot t^{2} \right]\cdot j$

b) The components of the position of the cannonball before hitting the ground is:

$x = (90\cdot \cos \theta)\cdot t$

$0 = 90\cdot \sin \theta - 6\cdot t$

After a quick substitution and some algebraic and trigonometric handling, the following expression is found:

$0 = 90\cdot \sin \theta - 6\cdot \left(\frac{x}{90\cdot \cos \theta} \right)$

$0 = 8100\cdot \sin \theta \cdot \cos \theta - 6\cdot x$

$0 = 4050\cdot \sin 2\theta - 6\cdot x$

$6\cdot x = 4050\cdot \sin 2\theta$

$x = 675\cdot \sin 2\theta$

The angle for a maximum horizontal distance is determined by deriving the function, equalizing the resulting formula to zero and finding the angle:

$\frac{dx}{d\theta} = 1350\cdot \cos 2\theta$

$1350\cdot \cos 2\theta = 0$

$\cos 2\theta = 0$

$2\theta = \frac{\pi}{2}$

$\theta = \frac{\pi}{4}$

Now, it is required to demonstrate that critical point leads to a maximum. The second derivative is:

$\frac{d^{2}x}{d\theta^{2}} = -2700\cdot \sin 2\theta$

$\frac{d^{2}x}{d\theta^{2}} = -2700$

Which demonstrates the existence of the maximum associated with the critical point found before.

c) The equation for the vertical component of position is:

$y = 45\cdot t - 6\cdot t^{2}$

The maximum height can be found by deriving the previous expression, which is equalized to zero and critical values are found afterwards:

$\frac{dy}{dt} = 45 - 12\cdot t$

$45-12\cdot t = 0$

$t = \frac{45}{12}$

$t = 3.75\,s$

Now, the second derivative is used to check if such solution leads to a maximum:

$\frac{d^{2}y}{dt^{2}} = -12$

Which demonstrates the assumption.

The maximum height reached by the cannonball is:

$y_{max} = 45\cdot (3.75\,s)-6\cdot (3.75\,s)^{2}$

$y_{max} = 84.375\,m$

7 0

3 years ago

Anyone wanna give me stuff in rocket league pc hehehehehe

adell [148]

Answer:

not really hehehehehe

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

What is the simplest form of this expression?

Salsk061 [2.6K]

Answer:
The answer is B.

6 0

2 years ago

Read 2 more answers

6 4/5 divided by 3 2/9

KiRa [710]

It would be: 6 4/5 / 3 2/9
= 34/5 / 29/9
You can re-write it as:
= 34/5 * 9/29
= 306/145

In short, Your Answer would be 306/145

Hope this helps!

4 0

2 years ago

The figure above shows the probability density function for the random variable x. What is P(3≤x<7)?

qwelly [4]

The value of the probability P(3≤x<7) is 1

<h3>How to evaluate the probability expression?</h3>

The expression is given as: P(3≤x<7)

This is calculated using:

P(3 ≤ x < 7) = P(3) + P(4) + P(5) + P(6)

Using the figure of the probability density function (see attachment), we have:

P(3 ≤ x < 7) = 0.30 + 0.30 + 0.20 + 0.20

Evaluate

P(3 ≤ x < 7) = 1

Hence, the value of the expression is 1

Read more about probability density function at:

brainly.com/question/15318348

#SPJ1

4 0

1 year ago