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DiKsa [7]
3 years ago
14

Write the following inexponential firm 100,000=

Mathematics
2 answers:
rjkz [21]3 years ago
6 0
100,000= 10^5 in exponential form
Galina-37 [17]3 years ago
4 0
In exponential for it could be 10 raised to the 5th power or 10^5
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Question 2.2 write down the general formula for the nth term of sequence. Mystic Rose
Misha Larkins [42]

Answer:

The nth term of an arithmetic sequence is given by. an = a + (n – 1)

5 0
2 years ago
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A quadratic function f(x)=ax2 passes through (0,0) and (5,5). write an equation for this function
krek1111 [17]

Answer:

y = (1/5)x² or  y = x²/5

Step-by-step explanation:

We have the function f(x) = ax² and are given that the point (5,5) is on the parabola.  We need to find 'a'.   f(x) can be replaced with 'y', so we can rewrite the equation as...

y = ax²    

We know that when x = 5, y = 5, so we have

5 = a(5²)      now simplify...

5 = 25a

5/25 = a

1/5 = a, so our equation becomes

(1/5)x² or  x²/5  (the expressions are equal)

8 0
3 years ago
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Sonbull [250]
The equation is y=(x-7)^2+7.

We are looking for a function with a vertex above the x-axis and a function that opens upward (has coefficient a > 0).

The first function opens downward and intersects the x-axis. The second function has a vertex below the x-axis. The third function satisfies our requirements. The fourth function has a vertex on the x-axis.

We can solve this algebraically with the knowledge that the real solutions of a quadratic are its x-intercepts. If there are no x-intercepts (because it lies entirely above or below the x-axis), then there are no real solutions. This is true when the discriminant b^2-4ac \ \textless \  0. You can see that from the quadratic formula. This holds true for both answers A and C, so to find the correct one, we remember that when the coefficient a of the x^2 term is positive, the graph opens upwards, so we choose C.
5 0
3 years ago
Read 2 more answers
Please help! 20 points + brainliest
klemol [59]

For the first one we divide every element by sqrt3

we get

q+2/sqrt3 =sqrt5/sqrt3

q=(sqrt5-2)/sqrt3

q=sqrt3*sqrt5-2*sqrt3/3

q=sqrt15-2sqrt3/3

which is the third option

For the second one

sqrt(2y-5) +4=8

first we move the 4 to the right

sqrt(2y-5)=4

we remove the square root by bringing to the power of two

2y-5=16

2y=21

y=21/2

y=10 1/2

third option

7 0
3 years ago
Find the value of x in the diagram below.
bulgar [2K]

Answer:

10

Step-by-step explanation:

13x + 5x = 180

18x = 180

x = 10

3 0
3 years ago
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