Answer:
The nth term of an arithmetic sequence is given by. an = a + (n – 1)
Answer:
y = (1/5)x² or y = x²/5
Step-by-step explanation:
We have the function f(x) = ax² and are given that the point (5,5) is on the parabola. We need to find 'a'. f(x) can be replaced with 'y', so we can rewrite the equation as...
y = ax²
We know that when x = 5, y = 5, so we have
5 = a(5²) now simplify...
5 = 25a
5/25 = a
1/5 = a, so our equation becomes
(1/5)x² or x²/5 (the expressions are equal)
The equation is

.
We are looking for a function with a vertex above the x-axis and a function that opens upward (has coefficient a > 0).
The first function opens downward and intersects the x-axis. The second function has a vertex below the x-axis. The third function satisfies our requirements. The fourth function has a vertex on the x-axis.
We can solve this algebraically with the knowledge that the real solutions of a quadratic are its x-intercepts. If there are no x-intercepts (because it lies entirely above or below the x-axis), then there are no real solutions. This is true when the discriminant

. You can see that from the quadratic formula. This holds true for both answers A and C, so to find the correct one, we remember that when the coefficient a of the

term is positive, the graph opens upwards, so we choose
C.
For the first one we divide every element by sqrt3
we get
q+2/sqrt3 =sqrt5/sqrt3
q=(sqrt5-2)/sqrt3
q=sqrt3*sqrt5-2*sqrt3/3
q=sqrt15-2sqrt3/3
which is the third option
For the second one
sqrt(2y-5) +4=8
first we move the 4 to the right
sqrt(2y-5)=4
we remove the square root by bringing to the power of two
2y-5=16
2y=21
y=21/2
y=10 1/2
third option
Answer:
10
Step-by-step explanation:
13x + 5x = 180
18x = 180
x = 10