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2 years ago

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Use the elimination method to solve the system of equations.3x-5y= -162x+5y=31

1 answer:

Sholpan [36]2 years ago

8 0

5x = 15
x = 3

3(3) - 5y = -16
9 - 5y = -16
5y = -16 - 9
5y = - 25
y = - 5

(3, -5)

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Directions: Calculate the area of a circle using 3.14x the radius

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$\qquad\qquad\huge\underline{{\sf Answer}}♨$

As we know ~

Area of the circle is :

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

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[ radius of the circle = half the measure of diameter ]

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<h3>Problem 1</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

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$\qquad \sf \dashrightarrow \:r = 2.2 \: mm$

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$\qquad \sf \dashrightarrow \:3.14 \times {4.84}^{}$

$\qquad \sf \dashrightarrow \:area \approx 15.2 \: \: mm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 2</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 3.7 \div 2$

$\qquad \sf \dashrightarrow \:r = 1.85 \: \: cm$

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$\qquad \sf \dashrightarrow \:3.14 \times (1.85) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 3.4225 {}^{}$

$\qquad \sf \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 3 </h3>

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$\qquad \sf \dashrightarrow \:area \approx216.31 \: \: cm {}^{2}$

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<h3>Problem 4</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

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<h3>problem 5</h3>

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8 0

1 year ago