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scZoUnD [109]
3 years ago
5

What is the slope of the midsegment parallel to AC?

Mathematics
1 answer:
Alenkinab [10]3 years ago
8 0

Answer:

The slope of midsegment which is parallel to AC is -4.

Step-by-step explanation:

We know that the slopes of parallel lines are same. It is given that the midsegment is parallel to AC, therefore the slope of AC and slope of midsegment is equal.

The slope of a line is

m=\frac{y_2-y_1}{x_2-x_1}

From the given figure it is noticed that A(3,7) and C(5,-1).

Slope of AC is

m=\frac{-1-(7)}{5-(3)} =\frac{-8}{2}=-4

Since the midsegment is parallel to AC, therefore their slopes are equal.

\text{Slope of midsegment}=-4

Therefore the slope of midsegment which is parallel to AC is -4.


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-3x+3c+5d-d

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Z to the power of 2 =1
stiv31 [10]

That would be written as:

z^{2} = 1


And the step-by-step equation would be:

z^{2} = 1 → we take the 2 to the right side of the equation and do the IO*

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z = 1 → final answer


*Ps - IO is not an existing term and stands for inverse operation. In this case, because when we take to 2 to the right side of the equation (the 2 is a power) it'll have to turn into a square root (because exponents and roots are inverse operations)



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HELP!<br> Find the Area of the triangle
Zigmanuir [339]

Answer:

A ≈ 65.8 m²

Step-by-step explanation:

Given 2 sides and the angle between them then the area (A) is

A = \frac{1}{2} bc sinA

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Line AC and line DB intersect at point P. Solve for angle BPQ.
taurus [48]

Answer:

Angle BPQ = 64°

Step-by-step explanation:

4x + 12 +2x = 90

6x + 12 = 90

     - 12    -12

6x = 78

x = 13°

BPQ = ((4(13) + 12)°

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Plz help me answer this
timofeeve [1]

Answer:

(-2, -8)

x = -2

y = -8

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define systems</u>

13x - 6y = 22

x = y + 6

<u>Step 2: Solve for </u><em><u>y</u></em>

<em>Substitution</em>

  1. Substitute in <em>x</em>:                              13(y + 6) - 6y = 22
  2. Distribute 13:                                 13y + 78 - 6y = 22
  3. Combine like terms:                      7y + 78 = 22
  4. Isolate <em>y</em> term:                                7y = -56
  5. Isolate <em>y</em>:                                         y = -8

<u>Step 3: Solve for </u><em><u>x</u></em>

  1. Define original equation:                    x = y + 6
  2. Substitute in <em>y</em>:                                     x = -8 + 6
  3. Add:                                                      x = -2
4 0
3 years ago
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