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stepladder [879]

2 years ago

9

a spinner has 4 equal sections: red, white, blue, and green. john spins the spinner and tosses a coin. which shows the sample sp

ace for spinning the spinner and tossing the coin?

1 answer:

Zielflug [23.3K]2 years ago

5 0

I think its 6, im not sure thoe

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Given a line segment with endpoints A(16, 8) and B(1, 3) what are the coordinates of the

blondinia [14]

Answer:

The line segment partitioned two-fifths from A to B is (10,6)

Step-by-step explanation:

First point from A to B is (16,8)

than find the difference between A to B i.e B - A

(1,3)-(16,8) = (-15,-5)

To measure the (2/5) difference we will multiply (-15,-5) with (2/5) which is equal to (-6,-2)

Now Add the difference to the first coordinate (point A) gives

Point of division = (16,8)+(-6,-2)

Point of division = (16-6, 8-2)

Point of division = (10,6)

4 0

2 years ago

In the figure, ∠ABD = 50° and ∠BCD = 60°. <br>Calculate ∠ADC and ∠ADO.

Brums [2.3K]

Answ

Step-by-step explanation:

5 0

1 year ago

Factor the expression.<br> X^2- 10xy + 24y?

lana66690 [7]

Answer:

The expression is not factorable with rational numbers. x^2-10xy + 24y

Step-by-step explanation:

7 0

2 years ago

You are choosing between two different cell phone plans. The first plan charges a rate of 23 cents per minute. The second plan c

jenyasd209 [6]

Answer:

357 minutes

Step-by-step explanation:

I subtracted 9 cents/minute from the 23 cents/minute to get 14 cents to get the difference between the two per minute charges. I then divided the monthly cost of $49.95 by .14 to get 356.79... So if you used 357 minutes in a month, the second plan would be 3 cents cheaper at $82.08 (.09 x 357= 32.13 + 49.95), vs. the first plan costing $82.11 (.23 x 357). At 356 minutes the first plan would still be cheaper.

3 0

2 years ago

Suppose a batch of metal shafts produced in a manufacturing company have a standard deviation of 1.5 and a mean diameter of 205

Crank

Answer:

$P(205-0.3=204.7$

$z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778$

$z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778$

So we can find this probability:

$P(-1.778$

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

$P = 1-0.9243 = 0.0757$

Step-by-step explanation:

Let X the random variable that represent the diamters of interest for this case, and for this case we know the following info

Where $\mu=205$ and $\sigma=1.5$

We can begin finding this probability this probability

$P(205-0.3=204.7$

For this case they select a sample of n=79>30, so then we have enough evidence to use the central limit theorem and the distirbution for the sample mean can be approximated with:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}$

And we can find the z scores for each limit and we got:

$z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778$

$z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778$

So we can find this probability:

$P(-1.778$

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

$P = 1-0.9243 = 0.0757$

6 0

2 years ago