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sleet_krkn [62]
3 years ago
14

What are the two types of primary safeguarding methods

Computers and Technology
1 answer:
hjlf3 years ago
8 0

Answer:

Guards and devices

Explanation:

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Analyze the following code. Is count < 100 always true, always false, or sometimes true or sometimes false at Point A, Point
GaryK [48]

Answer:

Point A: Always True

Point B: Sometimes false

Point C: Always False

Explanation:

In the given code snippet. Point A is the first statement within the While loop the statement System.out.println("Welcome to Java!"); will only be executed if the while condition evaluates to true.

At Point B, The statement count++ increases the value of the counter at every iteration, while it will be true for most occasions, at the last increament, this statement will be false that is at count=100, The condition will be false at this point just before program execution breaks out of the loop

Point C is outside of the loop, this happens when the given condition is no longer true.

8 0
3 years ago
Assume that a gallon of paint covers about 350 square feet of wall space. Create an application with a main() method that prompt
Makovka662 [10]

Answer:

<em>C++</em>

#include <iostream>

#include <cmath>

using namespace std;

///////////////////////////////////////////////////////////////////////

int noOfGallons(int wallArea) {

   int gallon = 350;

   int gallon_price = 32.0;

   float total_price = 0.0;

   ///////////////////////////////////////////

   float noOfGallons = (float)wallArea/(float)gallon;

   printf("No of gallons needed %.2f", noOfGallons);

   cout<<endl;

   //////////////////////////////////////////

  total_price = noOfGallons*gallon_price;

   return round(total_price);

}

int wallArea(int length, int width, int height) {

   int wall_area = length*width;

   int total_price = noOfGallons(wall_area);

}

///////////////////////////////////////////////////////////////////////

int main() {

   int length, width, height;

   ///////////////////////////////////////////

   cout<<"Enter length: ";

   cin>>length;

   

   cout<<"Enter width: ";

   cin>>width;

   

   cout<<"Enter height: ";

   cin>>height;

   

   cout<<endl;

   ///////////////////////////////////////////

   int total_price = wallArea(length, width, height);

  cout<<"Total price: $"<<total_price;

   ///////////////////////////////////////////

   return 0;

}

5 0
2 years ago
What is a Web application?
OLga [1]

Answer:

A web application is a computer program that utilizes web browsers and web technology to perform tasks over the Internet.

Explanation:

Web applications include online forms, shopping carts, word processors, spreadsheets, video and photo editing, file conversion e.t.c.

7 0
3 years ago
Quality answers will be appriciated! :)​
Naddika [18.5K]
<h2>1.</h2>

  1. F
  2. T
  3. T
  4. T
  5. F
  6. F
  7. T

________

<h2>2.</h2>

  1. A
  2. B
  3. D5*E5
  4. A

6 0
2 years ago
Read 2 more answers
write a 2d array c program that can capture marks of 15 students and display the maximum mark, the sum and average​
bekas [8.4K]

Answer:

#include <stdio.h>  

int MaxMark(int* arr, int size) {

   int maxMark = 0;

   if (size > 0) {

       maxMark = arr[0];

   }

   for (int i = 0; i < size; i++) {

       if (arr[i] > maxMark) {

           maxMark = arr[i];

       }

   }

   return maxMark;

}

int SumMarks(int* arr, int size) {

   int sum = 0;

   for (int i = 0; i < size; i++) {

       sum += arr[i];

   }

   return sum;

}

float AvgMark(int* arr, int size) {

   int sum = SumMarks(arr, size);

   return (float)sum / size;

}

int main()

{

   int student0[] = { 7, 5, 6, 9 };

   int student1[] = { 3, 7, 7 };

   int student2[] = { 2, 8, 6, 1, 6 };

   int* marks[] = { student0, student1, student2 };

   int nrMarks[] = { 4, 3, 5 };

   int nrStudents = sizeof(marks) / sizeof(marks[0]);

   for (int student = 0; student < nrStudents; student++) {              

       printf("Student %d: max=%d, sum=%d, avg=%.1f\n",  

           student,

           MaxMark(marks[student], nrMarks[student]),

           SumMarks(marks[student], nrMarks[student]),

           AvgMark(marks[student], nrMarks[student]));

   }

   return 0;

}

Explanation:

Here is an example using a jagged array. Extend it to 15 students yourself. One weak spot is counting the number of marks, you have to keep it in sync with the array size. This is always a problem in C and would better be solved with a more dynamic data structure.

If you need the marks to be float, you can change the types.

3 0
2 years ago
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