50 POINTS How do you express yourself and your creativity through computer science?

Which of the following is not a language commonly used for web programming?

DerKrebs [107]

The answer would be Assembly language as assembly language is not used for web development, but rather is a low level programming language.

Please mark branliest if this helped!!

7 0

3 years ago

Read 2 more answers

Hat are three machines or devices that depend on gravity to work?

jonny [76]

Some devices that depend on gravity to function include scales, showers, and satellites, to list a few.

6 0

3 years ago

Assume that a large number of consecutive IP addresses are available starting at 198.16.0.0 and suppose that two organizations,

Fiesta28 [93]

Answer & Explanation:

An IP version 4 address is of the form w.x.y.z/s

where s = subnet mask

w = first 8 bit field, x = 2nd 8 bit field, y = 3rd 8 bit field, and z = 4th 8 bit field

each field has 256 decimal equivalent. that is

binary denary or decimal

11111111 = 2⁸ = 256

w.x.y.z represents

in binary

11111111.11111111.11111111.11111111

in denary

255.255.255.255

note that 255 = 2⁸ - 1 = no of valid hosts/addresses

there are classes of addresses, that is

class A = w.0.0.0 example 10.0.0.0

class B = w.x.0.0 example 172.16.0.0

class C = w.x.y.0 example 198.16.8.1

where w, x, y, z could take numbers from 1 to 255

Now in the question

we were given the ip address : 198.16.0.0 (class B)

address of quantity 4000, 2000, 8000 is possible with a subnet mask of type

255.255.0.0 (denary) or

11111111.11111111.00000000.00000000(binary) where /s = /16 That is no of 1s

In a VLSM (Variable Length Subnet Mask)

Step 1

we convert the number of host/addresses for company A to binary

4000 = 111110100000 = 12 bit

step 2 (subnet mask)

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11110000.000000 /20

now we have added 4 1s in the 3rd field to reserve 12 0s

subnet mask: 255.255.16.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1  1  1 1 1 1

128 64 32 16 8 4 2 1

step 3

in the ip network address: 198.16.0.0/19 (subnet representation) we increment this using 16

that is 16 is added to the 3rd field as follows

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.0.1 - 198.16.15.255(last valid IP address)

Company B starts+16: 198.16.16.0 - 198.16.31.255

+16: 198.16.32.0- 198.16.47.255 etc

we repeat the steps for other companies as follows

Company B

Step 1

we convert the number of host/addresses for company B to binary

2000 = 11111010000 = 11 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 11 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11111000.000000 /21

now we have added 5 1s in the third field to reserve 11 0s

subnet mask: 255.255.8.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1 1 1  1 1 1

128 64 32 16 8  4 2 1

Step 3

Starting from after the last valid Ip address for company A

in the ip network address: 198.16.16.0/21 (subnet representation) we increment this using 8

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.16.1 - 198.16.23.255(last valid IP address)

Company C starts +16: 198.16.24.0- 198.16.31.255

+16: 198.16.32.0- 198.16.112.255 etc

Company C

Step 1

we convert the number of host/addresses for company C to binary

4000 = 111110100000 = 12 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11110000.000000 /20

now we have added 4 1s in the 3rd field to reserve 12 0s

subnet mask: 255.255.16.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1 1 1 1 1 1

128 64 32 16 8 4 2 1

Step 3

Starting from after the last valid ip address for company B

in the ip network address: 198.16.24.0/20 (subnet representation) we increment this using 16

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.24.1 - 198.16.39.255(last valid IP address)

Company C starts +16: 198.16.40.0- 198.16.55.255

+16: 198.16.56.0- 198.16.71.255 etc

Company D

Step 1

we convert the number of host/addresses for company D to binary

8000 = 1111101000000 = 13 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 13 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11100000.000000 /19

now we have added 3 1s in the 3rd field to reserve 13 0s

subnet mask: 255.255.32.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1  1  1 1 1 1 1

128 64 32  16 8 4 2 1

Step 3

Starting from after the last valid ip address for company C

in the ip network address: 198.16.40.0/20 (subnet representation) we increment this using 32

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.40.1 - 198.16.71.255(last valid IP address)

Company C starts +16: 198.16.72.0- 198.16.103.255

+16: 198.16.104.0- 198.16.136.255 etc

5 0

3 years ago

Write a C console application that will be used to determine if rectangular packages can fit inside one of a set of spheres. You

MatroZZZ [7]

Answer:

#include <cmath>

#include <iostream>

using namespace std;

int getSphereSize(double length, double breadth, double height) {

double diagonal = sqrt(length * length + breadth * breadth + height * height);

if (diagonal <= 4)

return 4;

if (diagonal <= 6)

return 6;

if (diagonal <= 8)

return 8;

if (diagonal <= 10)

return 10;

if (diagonal <= 12)

return 12;

return 0;

}

int main() {

double length, breadth, height;

int sphereCounts[5] = {0};

int sphereSize;

while (true) {

// Get dimensions of the box

cout << "Enter the dimensions of the box:\n";

cout << "Length: ";

cin >> length;

cout << "Breadth: ";

cin >> breadth;

cout << "Height: ";

cin >> height;

if (length <= 0 || breadth <= 0 || height <= 0)

break;

sphereSize = getSphereSize(length, breadth, height);

if (sphereSize == 0)

cout << "The box cannot fit in any of the spheres";

else

cout << "The box can fit in the " << sphereSize << "-inch sphere";

// Increment the counter

if (sphereSize == 4)

sphereCounts[0]++;

else if (sphereSize == 6)

sphereCounts[1]++;

else if (sphereSize == 8)

sphereCounts[2]++;

else if (sphereSize == 10)

sphereCounts[3]++;

else if (sphereSize == 12)

sphereCounts[4]++;

cout << "\n\n";

}

cout << "\nNumber of 4-inch spheres: " << sphereCounts[0];

cout << "\nNumber of 6-inch spheres: " << sphereCounts[1];

cout << "\nNumber of 8-inch spheres: " << sphereCounts[2];

cout << "\nNumber of 10-inch spheres: " << sphereCounts[3];

cout << "\nNumber of 12-inch spheres: " << sphereCounts[4];

cout << endl;

return 0;

}

Explanation:

The "cmath" library is included in the c++ program. The getSphereSize function is used to return the sphere size the rectangle dimension can fit into. It program continuously prompts the user for the length, breadth, and height of the rectangle and passes the values to the getSphereSize function in the while but breaks if any or all of the variable value is zero.

The sizes of the sphere objects in inches are collected in an array of five integer values of zeros and are incremented by one for every match with a rectangle.

7 0

3 years ago

Write a program that asks the user to enter the amount that he or she has budgeted for a month. A loop should then prompt the us

Dominik [7]

Answer:

import java.util.*;

public class Main {

public static void main(String[] args)

{

Scanner scan = new Scanner();

double budget=0, num=0, total=0;

System.out.println("Your budget for the month? ");

budget=scan.nextDouble();

System.out.println("enter all expense, and after that type -9999 to quit: ");

while(num != -9999)

{

total+=num;

num=scan.nextDouble();

}

if(total<=budget)

{

System.out.println("under budget by ");

System.out.println(budget-total);

}

else

{

System.out.println("over budget by ");

System.out.println(total-budget);

}

Explanation:

Take the budget as an input from user and store it to the budget variable.
Loop until user has entered all his expenses and keep on adding them to the total variable.
Check If the total is less than or equal to budget or otherwise, and then print the relevant message accordingly.

4 0

3 years ago