Round 96.9617186007 to the nearest tenth.

Mathematics

2 answers:

Pavlova-9 [17]4 years ago

6 0

if you're talking about the whole number, 100.96. if you're referring to decimal place values; 96.70.

underline the digit that you round to

circle the digit to the right

five or more goes up

four or less stays the same

everything behind becomes a zero.

Pani-rosa [81]4 years ago

5 0

96.9617186007 rounded to the nearest tenth is 97.0 because .9 gets rounded to a ten then you carry the one and it’s 97

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Find the point of intersection:<br> 3x=y-2<br> 6x=4-2y

IgorC [24]

Answer: (0, 2)

3x = y - 2
6x = 4 - 2y

3x = y - 2
- y - y
-y + 3x = - 2
- 3x - 3x
-y = - 3x - 2
/-1 /-1
y = 3x + 2

6x = 4 - 2y
+ 2y + 2y
2y + 6x = 4
- 6x - 6x
2y = - 6x + 4
/2 /2
y = -3x + 2

y = 3x + 2
y = -3x + 2

3x + 2 = -3x + 2
- 2 - 2
3x = -3x
/3 /3
x = 0

y = 3x + 2
y = 3(0) + 2
y = 2

(x, y) --> (0, 2)

Therefore, the two equations intersect at (0, 2)

Hope this helps!

7 0

3 years ago

How do i solve this question, anyone help

Degger [83]

Answer:

a. $\sqrt{52}$ cm or 7.21cm

b. $\sqrt{170}$ cm or 13.04cm

c. x= $\sqrt{136}$ cm or 11.66cm, y= $\sqrt{191}$ cm or 13.82cm

Step-by-step explanation:

a. You have to find the length of the other two sides of the triangle using the information already given. The first side is 6cm and the other is 12-9=4cm. Because it's a right-angled triangle you can use pythagoras

$c^2=a^2+b^2\\x^2=6^2+4^2\\x^2=36+16\\x^2=52\\x=\sqrt{52}cm \\x=7.21cm$