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____ [38]
3 years ago
9

Answer right then you get brainliest

Mathematics
1 answer:
tiny-mole [99]3 years ago
7 0
It's simple. The base of the rectangle is equal to the base of the big triangle. The height of the rettangle is equal to the base of the small triangle.

First you can calculate the area of the rectangle.

Ar = b*h = 5*8 = 40 in^2

Then you calculate the area of the two triangles

Small triangle area = (b*h)/2 = (6*5)/2 = 30/2 = 15 in^2

Big triangle area = (b*h)/2 = (8*7)/2 = 56/2 = 28 in^2

Sum the area of all polygons.

40+15+28 = 83 in^2

Answer C
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The length of a rectangle is 3 yd more than twice the width, and the area of the rectangle is 54 yd?. Find the dimensions of the
s344n2d4d5 [400]

Answer:

The length of the rectangle is 37 yards, and the width of the rectangle is 17 yards.

Step-by-step explanation:

Given that the length of a rectangle is 3 yards more than twice the width, and the area of the rectangle is 54 yards, the following calculation must be performed to find the dimensions of the rectangle, knowing that the area of a rectangle arises from multiplying its base by its height:

2X + 3 + X = 54

3X + 3 = 54

3X = 54 - 3

X = 51/3

X = 17

(17 x 2) + 3 = 37

Therefore, the length of the rectangle is 37 yards, and the width of the rectangle is 17 yards.

4 0
3 years ago
PLEASE HELP ME ASAP :D
Ivanshal [37]

Answer: The answer is 5^5.

Step-by-step explanation:I don't know

sorry for taking so long

i got this from my sis and she just didn't give me an explanation.

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