Answer:
405 Problems
Step-by-step explanation:
- One student in class has 15 problems.
- There are 27 students in the class.
Let's <u>multiply</u> 15 by 27.

<em>In all, there would be 405 problems assigned to the whole class.</em>
I got 130.24 square feet. Hope that helps.
You have to use the quadratic formula to solve this. The zeros of this quadratic are 2 + sqrt2/2 and 2 - sqrt2/2, which in "real" numbers is 1.707 and .2928
Let
width,w
length, l = 1.6w ...eqn 1
area, a = l × w ...eqn 2
subst for l in eqn 2
a = 1.6 w × w = 4000
4000 = 1.6 w^2
w^2 = 2500
w = 50
subst for w in eqn 1
l = 50 x 1.6 = 80
length = 80 yds
width = 50 yds