<h3>
Answer: 7/10</h3>
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Explanation:
There are 30 days in April. Since it rained 9 of those days, the empirical probability of it raining in April is 9/30 = (3*3)/(3*10) = 3/10.
If we assume that the same conditions (ie weather patterns) hold for May, then the empirical probability of it raining in May is also 3/10. By "raining in May", I mean specifically raining on a certain day of that month.
The empirical probability of it not raining on the first of May is therefore...
1 - (probability it rains)
1 - (3/10)
(10/10) - (3/10)
(10-3)/10
7/10
We can think of it like if we had a 10 day period, and 3 of those days it rains while the remaining 7 it does not rain.
Answer:
1/6
Step-by-step explanation:
this seems too simple but...
6/6 would be all the cupcakes the whole
so if 5/6 are gone than
1/6 are left
2.3 + w > 18
-2.3 -2.3
w > 15.7
Answer:
y=1/3x_1/5=1/3×15=5_1/5×15=3. 5_3=2
Answer:
The answer would be 2,187
1). solution
3³÷3^(-4)
3³×3⁴. ( power sign changes when divide sign change into multiply)
2,187