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OLga [1]
3 years ago
12

Circle M is shown. Line segments J L and H K are diameters that intersect at center point M. Angle K M L is 25 degrees.

Mathematics
1 answer:
lisov135 [29]3 years ago
7 0

Answer:

Arc(JH) = 0.44r

Step-by-step explanation:

In this question radius of the circle is not given.

Given information: Line segments J L and H K are diameters that intersect at center point M, m∠KML = 25°.

Using given information draw a diagram as shown below.

From the below figure it is clear that ∠KML and ∠JMH are vertically opposite angles.

If two lines intersect each other then vertically opposite angles are equal.

m\angle KML=n\angle JMH=25^{circ}

Let the radius of the circle M is r.

The formula for arc length is

s=2\pi r(\frac{\theta}{360})

where, r is radius of the circle and θ in degree.

Acr(JH)=2\pi r(\frac{25}{360})

Acr(JH)=0.436332313r

Acr(JH)\approx 0.44r

Note: If the value of r is given, then substitute the value of r in the above equation and round to the nearest tenth of a centimeter.

Therefore, the length of arc (JH) is 0.44r.

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This is the polynomial fit equation:
T(h)=20.2-3.6h-0.875h^2
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Here is a link to the spreadsheet  (<span>https://docs.google.com/spreadsheets/d/17awPz5U8Kr-ZnAAtastV-bnvoKG5zZyL3rRFC9JqVjM/edit?usp=sharing)</span>

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