Let the constant of variation be c.
We are given that y varies inversely with 2.5x, this means that:
y = (c) / (2.5x)
This can be written as:
2.5xy = c
Now, we a re given that y = 5.6 at x = 30.
Substitute with these values in the equation to get the value of c as follows:
2.5xy = c
2.5(30)(5.6) = c
c = 420
Therefore, the equation that describes the relation is:
2.5xy = 420
(-7,-12) s it both down and to the right of the origin
So, 40 Customers are waiting at 10 A.M.
According to statement
Number of customers arrives at coffee shop per hour = 100
Capacity of shop for per minute per customer = 0.8 minute
Capacity of shop for customers per hour = 80
Find number of customers are by
Queue growth rate = Demand - Capacity
Put the values in the formula and find the growth rate
So,
Queue growth rate= 100 - 80 = 20.
Length of queue at 10 a.m. = 2 × 20 = 40.
So, 40 Customers are waiting at 10 A.M.
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the whole exam will be 100%, and let's say that's "x" questions, but we also know that 9 is 60% of that so
You did not include the choices. However, I answered one that just included them. I've included the possible answers below and then the correct answers.
<span>A multiple of Equation 1.
B. The sum of Equation 1 and Equation 2
C. An equation that replaces only the coefficient of x with the sum of the coefficients of x in Equation 1 and Equation 2.
D. An equation that replaces only the coefficient of y with the sum of the coefficients of y in Equation 1 and Equation 2.
E. The sum of a multiple of Equation 1 and Equation 2.
</span>A, B and E.
Adding and multiplying the terms allow them to keep working. However, you must make sure that each variable is changed each time. Not just one as in C and D.
