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2 years ago

9

Write equation in standard form if x-intercept is 5 and y-intercept is 3.

1 answer:

Vlad [161]2 years ago

5 0

The equation in standard form is: y=5x+3

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A football player punts a ball. The path of the ball can be modeled by the equation y = –0.004x2 + x + 2.5, where x is the horiz

Galina-37 [17]

The answer is <span>252.5 ft

</span><span>y = –0.004x</span>²<span> + x + 2.5
Let's take y = 0 and we'll get the quadratic equation:

</span>–0.004x² + x + 2.5 = 0
The general formula for quadratic equation is:
ax² + bx + c = 0

a = -0.004
b = 1
c = 2.5

$x_{1,2} = \frac{-b+/- \sqrt{ b^{2}-4ac} }{2a} =\frac{-1+/- \sqrt{ 1^{2}-4*(-0.004)*2.5} }{2*(-0.004)} = \frac{-1+/- \sqrt{1+0.04} }{-0.008} = \\ 
=\frac{-1+/- \sqrt{1.04} }{-0.008} = \frac{-1+/-1.02}{-0.008}$

$x_1=\frac{-1+1.02}{-0.008} = \frac{0.02}{-0.008} = -2.5 \\ 
x_2=\frac{-1-1.02}{-0.008} = \frac{2.02}{-0.008} = 252.5$

Since distance cannot be negative (x1), the correct answer is x2 = 252.5 ft

5 0

2 years ago

Read 2 more answers

The center of a hyperbola is (−4,3) , and one vertex is (−4,7) . The slope of one of the asymptotes is 2.

Monica [59]

Answer:

The answer to your question is below

Step-by-step explanation:

C (-4, 3)

V (-4, 7)

asymptotes = 2 = $\frac{b}{a}$

- This is a vertical hyperbola, the equation is

$\frac{(y - k)^{2} }{a^{2} } + \frac{(x - h)^{2} }{b^{2} } = 1$

slope = 2

a is the distance from the center to the vertex = 4

b = 2(4) = 8

$\frac{(y - 3)^{2} }{4^{2} } + \frac{(x + 4)^{2} }{8^{2} } = 1$

$\frac{(y - 3)^{2} }{16} + \frac{(x + 4)^{2} }{64} = 1$

7 0

3 years ago

Read 2 more answers

Using your knowledge of exponential and logarithmic functions and properties, what is the intensity of a fire alarm that has a s

Ierofanga [76]

Option B:

$I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}$

Solution:

Given sound level = 120 decibel

To find the intensity of a fire alarm:

$$\beta=10\log\left(\frac{I}{I_0} \right)$

where $I_0=1\times10^{-12}\ \text {watts}/ \text m^2}$

Step 1: First divide the decibel level by 10.

120 ÷ 10 = 12

Step 2: Use that value in the exponent of the ratio with base 10.

$10^{12}$

Step 3: Use that power of twelve to find the intensity in Watts per square meter.

$$10^{12}=\left(\frac{I}{I_0} \right)$

$$10^{12}=\left(\frac{I}{1\times10^{-12}\ \text {watts}/ \text m^2} \right)$

Now, do the cross multiplication,

$I=10^{12}\times1\times\ 10^{-12} \ \text {watts}/ \text m^2}$

$I=1\times\ 10^{12-12} \ \text {watts}/ \text m^2}$

$I=1\times\ 10^{0} \ \text {watts}/ \text m^2}$

$I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}$

Option B is the correct answer.

Hence $I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}$ .

5 0

3 years ago

In a recent flu epidemic, the number of flu cases increased by 40% each week. There were 3,000 flu cases during the first week o

Alborosie

Answer:

2880

Step-by-step explanation:

The total number of people affected by flu during the 2nd and 3rd week of January, 1200 + 1680 = 2880

5 0

2 years ago

I need help solving it

blagie [28]

X2-64=0
x2=64

x=8 because when multiplied by itself, and plugged back in, it works

8 0

2 years ago

Read 2 more answers