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AleksandrR [38]
2 years ago
6

Enter your answer in the provided box. what is the emf of a cell consisting of a pb2 / pb half-cell and a pt / h / h2 half-cell

if [pb2 ] = 0.57 m, [h ] = 0.090 m and ph2 = 1.0 atm ? v
Mathematics
1 answer:
s2008m [1.1K]2 years ago
6 0

The emf of a cell is mathematically given as

E_{cell}  = 0.0532 v

<h3>What is the emf of a cell?</h3>

Generally, the equation for emf  is mathematically given as

Pb/Pb^2^+ //\ H / H_2

where,

Pb is lead

H is hydrogen

Pb^{2+} / Pb has a standard reduction potential of -0.126 volts, while

H_2 / H_2 has a standard reduction potential of 0.0 volts.

E_{cell }= E^0_{cell} - 0.059/n log 1/[Pb^2^+] x [H^+]^2

E_{cell} = 0.126 -  0.059/2 log 1  /  [0.57] x [0.09]^2

E_{cell}  = 0.0532 v

Read more about emf

brainly.com/question/15121836

#SPJ4

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If a 2-kg block compresses a spring 800mm from its relaxed state, how much potential energy does the block have due to the sprin
Tju [1.3M]

Answer:

8 Joule

Step-by-step explanation:

Mass of block = 2 kg

Displacement = x = 800 mm = 0.8 m

Spring constant = k = 25 N/m

Potential Energy of a spring

Work done = Difference in Potential Energy

Work Done = Δ P.E.

\Rightarrow \Delta\ P.E.=\frac{1}{2}kx^2

⇒P.E. = 0.5×25×0.8²

⇒P.E. = 8 Nm = 8 Joule

Here already the spring constant and displacement is given so the mass will not be used while calculating the potential energy.

5 0
3 years ago
A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 ce
julsineya [31]

Answer:

The proportion of students whose height are lower than Darnell's height is 71.57%

Step-by-step explanation:

The complete question is:

A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.

What proportion of proportion of students height are lower than Darnell's height.

Answer:

We first calculate the z-score corresponding to Darnell's height using:

Z=\frac{X-\mu}{\sigma}

We substitute x=161.4 , \mu=150, and \sigma=20 to get:

Z=\frac{161.4-150}{20} \\Z=0.57

From the normal distribution table, we read 0.5 under 7.

The corresponding area is 0.7157

Therefore the proportion of students whose height are lower than Darnell's height is 71.57%

8 0
3 years ago
What percent of 390 is 39?
Brums [2.3K]
I believe 10% because 390 and 39 are exactly the same numbers almost
5 0
3 years ago
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vaieri [72.5K]
The answer is 7 because the mean is an average. So if you add up all the numbers and then divide that number by the amount of numbers listed then that will get you your answer which is 7

4+5+6+7+8+9+10=49
49/7=7
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3 years ago
Hey i need some help :)
melamori03 [73]

Answer:

[See Below]

Step-by-step explanation:

\boxed{Hey~There!}

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\boxed{The~answer~is: x > -3}

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