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koban [17]
3 years ago
12

The cost of flying a passenger plane from point A to point B is ​$70 comma 00070,000. The airline flies this route four times pe

r day at 7 ​AM, 10 ​AM, 1 ​PM, and 4 PM. The first and last flights are filled to capacity with 240240 people. The second and third flights are only half full. Find the average cost per passenger for each flight.
Mathematics
2 answers:
Kruka [31]3 years ago
5 0

Answer: The cost will be $291.70 and $583.40 for the first and the last and for the second and third flights, respectively.

Step-by-step explanation: The cost is $70,000, the full capacity of seats is 240 and half capacity is 120.

In the first and last flights, which have the full capacity, the average cost per passenger is:

C = \frac{70,000}{240} = 291.70

In the second and third ones, the average cost is:

C = \frac{70,000}{120} = 583.4

The average cost per passenger for the first and the last flight are $291.70, while for the second and third are $583.4

Vladimir [108]3 years ago
4 0

Answer:

I. $291.67 per passenger

II. $583.33 per passenger

Step-by-step explanation:

The cost of flying the passenger plane from A to B is $70,000.

If the Capacity of the plane is 240 people.

(I)At 7A.M and 4P.M., the average cost per passenger is given as:

Average Cost=Total Cost/Number of Passengers

=70000/240=$291.67 per passenger

(II)At 10AM and 1PM, the flight is only half full, it has 120 passengers.

Average Cost = 70000/120=$583.33 per passenger

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