Using the z-distribution, the 90% confidence interval for the difference of proportions is given by: (-0.0534, 0.0434).
<h3>What is the mean and the standard error for the distribution of differences?</h3>
For each sample, the mean and the standard error are given as follows:
.
.
For the distribution of differences, they are given by:
.
<h3>What is the confidence interval?</h3>
The interval is given by:
In this problem, we have a 90% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 1.645.
Hence the bounds of the interval are:
More can be learned about the z-distribution at brainly.com/question/25890103
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8 is divisible by 102 ... answer ; 816 divided by 8 = 102
Answer:
a. We are confident that the mean admission rate is between 52.8% and 75.0%
Step-by-step explanation:
When you have an unknown population parameter you can use a sample to delimit an interval in which this parameter is, the interval is called confidence interval and the confidence level is the probability of the parameter being inside the interval. The confidence interval is represented by a pair of numbers, in this case, the pair is (52.8%, 75.0%) and the confidence level is 95%, with that level you can say that you're confident that the mean admission rate is between (52.8%, 75.0%).
Step-by-step explanation:
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Answer:
A.
Step-by-step explanation:
5x8 enlarged to 10x16
10 is 5x2 and 16 is 8x2
