3 years ago

Simplify radical 125

Mathematics

1 answer:

timurjin [86]3 years ago

7 0

Answer:

5√5

Step-by-step explanation:

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What is the quotient 2y^-6y-20/4y+12 ÷ y+5y+6/3y^2+28y+27

malfutka [58]

Answer with explanation:

$\rightarrow \frac{\frac{2y^2-6 y-20}{4 y+12}}{\frac{y^2+5 y+6}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{y^2-3y-10}{2 y+6}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{(y-5)(y+2)}{2 (y+3)}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{(y-5)(y+2)}{2 (y+3)}} \times {\frac{3 y^2+28 y+27}{(y+2)(y+3)}}\\\\ \rightarrow\frac{(y-5)\times(3 y^2+28 y+27)}{2 (y+3)^2}}$

→y²+5y+6

=y²+3 y+2 y+6

=y×(y+3)+2×(y+3)

=(y+2)(y+3)

→y² -3 y-10

=y² -5 y+2 y -10

=y×(y-5)+2×(y-5)

=(y+2)(y-5)

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2 years ago

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Which of the following are possible values of r?<br><img src="https://tex.z-dn.net/?f=%20%7Br%7D%5E%7B2%20%7D%20%20%3D%20%20%5Cf

marshall27 [118]

Answer:

$r=\frac{\sqrt{3} }{4}$ and $r=-\frac{\sqrt{3} }{4}$

Step-by-step explanation:

when you solve for r in the given equation, you need to apply the square root property, which gives positive and negative answers (both should therefore be considered):

$r^2=\frac{3}{16} \\r=+/-\sqrt{\frac{3}{16}} \\r=+/-\frac{\sqrt{3} }{4}$

then you need to include these two possible solutions:

$r=\frac{\sqrt{3} }{4}$ and $r=-\frac{\sqrt{3} }{4}$

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2 years ago