Answer:
The horsepower required is 235440 watt.
Step-by-step explanation:
To find : What horsepower is required to lift an 8,000 pound aircraft six feet in two minutes?
Solution :
The horsepower formula is given by,

Where, W is the horsepower
m is the mass m=8000 pound
g is the gravitational constant g=9.81
t is the time t= 2 minutes
h is the height h=6 feet
Substitute all values in the formula,



Therefore, The horsepower required is 235440 watt.
A of trapezium = ((a+b)/2)(h)
A = ((10+10+4)/2)(8)
A = (24/2)(8)
A = 12(8)
A = 94
The area is 94ft²
Answer:
x=
2
/3
y+2
Step-by-step explanation:
Let's solve for x.
−6x+4y=−12
Step 1: Add -4y to both sides.
−6x+4y+−4y=−12+−4y
−6x=−4y−12
Step 2: Divide both sides by -6.
−6x
/−6
=
−4y−12
/−6
x=
2
/3
y
=x=
2
/3
y+2
<h3><u>
brainliest please?</u></h3>
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This basically means 500 x 10. Unit form is just writing out the numbers. The answer is 5,000;