I'm guessing you find the length of the hypotenuse using the pythagorean theorem.
a² + b² = c² a and b are the legs and c is the hypotenuse
15² + 8² = c²
225 + 64 = c²
289 = c²
√289 = √c²
17 = c
hope that helps, God bless!
Answer:
The factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....
Step-by-step explanation:
The given expression is:
2q²-5pq-2q+5p
Make a pair of first two terms and last two terms:
(2q²-5pq) - (2q-5p)
Now factor out the common factor from each group.
Note that there is no common factor in second group. So we will take 1 as a common factor.
q(2q-5p) -1(2q-5p)
Now factor the polynomial by factoring out the G.C.F, 2q-5p
(2q-5p) (q-1)
Thus the factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....
Answer:
$-17.82
Step-by-step explanation:
he has $-17.82 because 30.85(the amount he has)-48.67(the amount he paid for) = -17.82
