All categories

3 years ago

At 1 pm there were 16 seagulls on the beach.At 3 pm they were 40 seagulls what is the constant rate of change

Mathematics

1 answer:

Eva8 [605]3 years ago

5 0

Answer:

12 every hour

Step-by-step explanation:

12 + 12 = 24 +16 = 40

You might be interested in

Pls help i need help with this been working fo a bit

Alex Ar [27]

$\\ \sf\Rrightarrow \dfrac{6}{7}x-\dfrac{2}{5}y+\dfrac{5}{7}(y+x)$

$\\ \sf\Rrightarrow \dfrac{6}{7}x-\dfrac{2}{5}y+\dfrac{5}{7}x+\dfrac{5}{7}y$

$\\ \sf\Rrightarrow \dfrac{6}{7}x+\dfrac{5}{7}x-\dfrac{2}{5}y+\dfrac{5}{7}y$

$\\ \sf\Rrightarrow \dfrac{11}{7}x+\dfrac{-14+25}{35}y$

$\\ \sf\Rrightarrow \dfrac{11}{7}x+\dfrac{11}{35}y$

Done!

8 0

2 years ago

Read 2 more answers

Jon said, “m-1 is always greater than 1-m. Do you agree with Jon? LIURE DOMPE DI EL דים כר LECCE RE: A. Agree, because m is a po

Trava [24]

Given that Jon said,

"m-1 is always greater than 1-m"

we want to find how true the statement is;

$\begin{gathered} \text{for m = positive integer.} \\ m=5 \\ m-1=5-1=4 \\ 1-m=1-5=-4 \\ So,\text{ } \\ m-1>1-m \\ \text{for m equals positive integer } \end{gathered}$

secondly for negative values of m;

$\begin{gathered} m=-5 \\ m-1=-5-1=-6 \\ 1-m=1-(-5)=1+5=6 \\ So, \\ m-1$

So, the statement "m-1 is always greater than 1-m" is false.

Because 1- m is greater than m-1 when m is a negative integer.

Therefore, I Disagree, because 1- m is greater than m-1 when m is a negative integer

3 0

1 year ago

I need help on this:The perimeter of the square below is 36 yards. What is the length of each side?

jeka57 [31]

Hi so remember the perimeter of a square is 4 times the side. so if the perimeter is 36 then you can divide 36 by 4 to get the answer 9.

36=4^x
36=4x
36/4=x
9=x

to cross check if ever unsure times the (side) by 4 if it matches the given perimeter.

3 0

3 years ago

Read 2 more answers

What is the probability of randomly selecting a month pf year and not getting a month that ends in y?

Umnica [9.8K]

Answer:

2/3

Step-by-step explanation:

The months whose names end in 'y' include Jan, Feb, May, Jul. The probability of randomly selecting a month whose name ends in 'y' is 4/12 (remember that there are 12 months in a year), or 1/3.

Thus, the probability of selecting a month whose name does NOT end in 'y' is 8/12, or 2/3. Note that this event is the 'complement' of the first event:

P(name does not end in 'y') = 1 - P(name does not end in 'y') = 1 - 1/3 = 2/3

8 0

2 years ago

Q= 4(a+b) solve for d

alukav5142 [94]

Answer:

$b= \frac{q - 4a}{4}$

Step-by-step explanation:

ill suppose that you mean : "solve for b" not for d, since there is no d term in the formula given. So:

$q = 4(a + b) \\ q = 4a + 4b \\ 4a + 4b = q \\ 4a + 4b - 4a = q - 4a \\ 4b = q - 4a \\ b = \frac{q - 4a}{4}$

7 0

2 years ago